## ICSE Books and Study Material Subjectwise | ISC Reference Books List

Council for the Indian School Certificate Examination (CISCE) organizes ICSE Exam for all the affiliated schools. The ICSE Board frames exams in a way to give an in-depth understanding of concepts covering all the important topics. Books are very much essential before you begin with your preparation and also to have a better understanding of concepts.

ICSE Books prevailing over here acts an important study material and resources for all those preparing for their Board Exams. Not just students, but also teachers rely on these Indian Certificate of Secondary Education Books while teaching a particular subject.

• ICSE Solutions
• Selina Solutions
• ML Aggarwal Solutions
• RS Aggarwal Solutions

Have a glance at the ICSE Subjectwise Prescribed Textbooks along with the Authors by referring further. The Textbooks recommended by subject experts act as an instruction manual for students.

## ICSE Subjectwise List of Prescribed Textbooks

You can go through the list of prescribed books for all the subjects as reading from multiple sources will just confuse you. ICSE Textbooks prevailing will provide in-depth knowledge about the particular subject. You can complete your homework or assignments simply by using these books. Utilize these ultimate preparation tools and make your learning complete. You can gain insights into the Syllabus Topics.

To help all such students preparing for their ICSE Board Exams we have compiled the best reference books that aid in your preparation. You will have everything covered in these books right from basic standard to high standard. All the concepts are explained in a descriptive manner and simple language. All the ISC Books and Study Material Present are given as per the Latest CISCE Curriculum and followed by many schools.

### English(01)

PAPER 1. (Language)
No specific book is being recommended for background reading.
PAPER 2. (Literature in English)

• DRAMA: The Merchant of Venice
(Shakespeare’s unabridged play by A.W. Verity)
OR
• The Mousetrap – Agatha Christie
• TREASURE TROVE – A collection of ICSE Poems & Short Stories (Evergreen Publications (India) Ltd. New Delhi).

Poetry

• Heart of a Tree by Henry Cuyler Bunner
• After Blenheim by Robert Southey
• The Cold Within by James Patrick Kinney
•  The Patriot by Robert Browning
•  Nine Gold Medals by David Roth
• Television by Roald Dahl
•  Daffodils by William Wordsworth
• Bangle sellers by Sarojini Naidu
•  Abu Ben Adheim by Leigh Hunt
•  I Know why the Caged Bird Sings by Maya Angelou

Prose

1.  Short Stories:

(i) Chief Seattle’s Speech
(ii) The Old Man at the Bridge by Earnest
Hemmingway
(iii) A Horse and Two Goats by R.K. Narayan
(iv) Hearts and Hands by O’ Henry
(v) A Face in the Dark by Ruskin Bond
(vi) Angel in Disguise by T.S. Arthur
(vii) The Little Match Girl by Hans Christian
Andersen
(viii) The Blue Bead by Norah Burke
(ix) My Greatest Olympic Prize by Jesse
Owens
(x) All Summer in a Day by Ray Bradbury

2. Animal Farm by George Orwell

3. Call of the Wild by Jack London

Indian Languages

### AO NAGA(42)

• Mejen O 2nd edition.
(An Anthology of Poems and Short Stories by Contemporary Ao writers, JMS Publication).
• Khristan Aeni Aoba 2nd edition.
(A translation of John Bunyan’s ‘The Pilgrim’s Progress’, A BAM Publication).
• Akumlir Wadang by L. Imti Aier.

### Assamese(02)

• Karengar Ligiri (Drama): by Jyoti Prasad Agarwala
•  Saudor Puteke Naau Meli Jai (Novel) by Homen Buragohain
• Kabita Manjuri (a collection of poems)
• Asomiya Chuti Galpar Prabah (a collection
of short stories)

### Bengali(03)

(i)Sonkolita: A collection of ICSE Short Stories & Poems by Power Publishers, Kolkata

Short Stories:

• Ginni by Rabindranath Tagore.
• Laloo by Sarat Chandra Chattopadhyay
• Canvassar by Banaphul
• Naam by Narendranath Mitra
• Debotar Jonmo by Shibram Chakraborty
•  Neel Manusher Kahini by Sunil Gangyopadhyay
• Gandhota Baro Sandehojanak by Shirshendu Mukhopadhyay
• Lokti by Humayun Ahmed

(ii)Poems:

• Bangabhumir prati by Madhusudan Dutta
• Shobhotar prati by Rabindranath Tagore
• Kuli-Mojur by Najrul Islam
• Aabar Asibo Phire by Jibananda Das
• Siri by Sukanta Bhattacharya
• Rabindranather Prati by Buddhadeb Basu
• Phul Futuk Na Futuk by Subhash Mukhopadhay
• Amalkanti by Nirendranath Chakraborty
• Babu Bolen by Shankha Ghosh
• Kho-Kho by Amitabha Dasgupta

(iii) Novel: Chander Pahar by Bibhutibhushan Bandyopadhyay
(iv) Drama: Jambo by Mohit Chattopadhyay

### DZONGKHA(26)

(i) Gyalse Laglen by Prose (Reader VIII)
(ii) Legshed Langdor Shenjed Proverbs
(iii)Biography of Ashi Nangse

### GARO(40)

(i) Kadimgimin Seanirang Bak II: C compiled by Lindrid D. Shira

1. A Chikrangni Nokma Songa by Llwellyn R. Marak
2. Nokpante by Brucellina G momin
3. Balpakram by Llwellyn R. Marak
4. David Livingstone by Tojing S Sangma
5. Sepoy Mutiny ong gniko Jumang Niksoa by Vinthon M. Momin
6. Rev. Thangkan K. Sangma by Lindrid D. Shira
7. Changsao Dakgrikram A.bao Krismas Salo by Mackenson Rongmuthu
8. Garo Hills Damgipin A.gisi by Rev. Gilbert K Marak
9. Ahaia Ba Medong Ra.ona by Aldrich Ch. Marak
10. Chengoni A chik Kattarang by Dewansing Rongmuthu
11.Jakgitel Bil Aro Miksongani by Keneth M. Momin
12. Turani Chatro chatrirangni Bajengdeba Ramako Re.ani Bewal by Wilson K Marak
13. A song De.a by Aldrich Ch. Momin
14. Kangalni Dal Gipa Mande ong.ani by Lindrid D. Shira
15. Indiani Jakgitelanina Krenggiparangni Pegipa by Icylian R. Marak

(ii)Poetry

Chason Gital A.Chik Poetryrang  Compiled by Keneth M.Momin

1. Ma.ani Ka.saa by H. B. Sangma
2. Bidan Chimik by S. S. Marak
3. A. Songtagna Sintea by S. S. Sangma
4. Katta Pagitcham Niam Songittcham by D. S. Rongmuthu
5. O Sia by J. Rongmuthu
6. Ka.saa by Keneth Momin
7. Ritimkari by B. S. Sangma
8. Cha.asia by B. S. Bangshall
9. Saljong Tasin Me chik by M.R. Sangma
10. A.gilsak Dal.begipa Alda Nok by M. Rongmuthu

(iii) Veniceni Badinggipa by (Late) Mackenson
Rongumuthu.

### Gujarathi(04)

Sahitya Gurjar: A collection of ICSE Short Stories and Poems.

(i) Short Stories: (All short stories to be studied)
1.Khari Maa by Ramanlal Desai
2.Parivartan by Gaurishankar Joshi (Dhumketu)
4.Jamunanu Poor by Ramnarayan Pathak
5.Ladu nu Jaman by Pannalal Patel
6. Annjalpani by Pitambar Patel
7.Maji no pyalo by Gulabdas Broker
9.Dadano Dallo by Ila Arab Mehta

(ii) Poems: (All poems to be studied)
1.Vaishnavjan by Narsinh Mehta
2. Lochan Man no Jagado by KaviDayaram
3. Pranam Mara by Ramnarayan Pathak
4.Ae Nishal Ae Savar by Sundarji Betai
5. Chha Rutuo by Umashankar Joshi
7. Boliye na Kain by Rajendra Shah
8. Gram Mata by Sursingji Gohil “ Kalapi”
9. Panchika by Mukesh Joshi
10. Subhashito
(iii) Novel: Vaansano Ankur by Smt Varsha Adalja
(iv) Ekanki Gurjar A collection of ICSE One Act
Plays: (Gurjar Granthratna Karyalaya,
1.Vruksh by Labhshankar Thakar
2.Karna Kunti by Manubhai Pancholi
3.Raja Ladu Sinh by Dr Shiv Shankar Joshi
4.Hukum Malik by Chinu Modi
5.Lagnana Umedwar by Jyotindra Dave
6.Deshbhakt Jagdusha by Raman Lal Soni

### Hindi(05)

Recommended for background work: Saras Hindi Vyakaran (Evergreen Publications, New Delhi)

Sahitya Sagar: A collection of ICSE Short
Stories &Poems. (Evergreen Publications, New
Delhi)
(i) Short Stories:
1. Baat Athanni Ki by Sundarshan
2. Kaki by Siyaram Sharan Gupta
3. Maha Yagya Ka Puruskar by Yashpal
4. Netaji Ka Chasma by Swayam Prakash
5. Apna Apna Bhagya by Jainendra Kumar
6. Bade Ghar Ki Beti by Premchand
8. Jamun Ka Ped by Krishna Chander
9. Bhede Aur Bhediyen by Hari S hankar
Parsai
10. Do Kalakar by Mannu Bhandari
(ii) Poems:
1. Sakhi byKabir Das
2. Girdhar Ki Kundaliyan by Girdhar Kavi
Rai
3. Swarg Bana Sakte Hai by Ramdhari Singh
Dinkar
4. Wah Janmabhumi Meri by Sohanlal
Dwivedi
5. Megh Aaye by Sarveshwar Dayal Saxena
6. Sur Ke Pad by Surdas
7. Vinay Ke Pad by Tulsidas
8. Bhichhuk by Surya Kant Tripathi ‘Nirala’
9. Chalna Hamara Kam Hai by Shivmangal
Singh ‘Suman’
10. Matri Mandir Ki Or by Subhadra Kumari
Chauhan
(iii) Novel: Naya Raasta by Sushma Agarwal

(iv) Ekanki Sanchay – A collection of ICSE One Act Plays: (Evergreen Publications, New Delhi)
1. Sanskar Aur Bhavna by Vishu Prabhakar
2. Bahu Ki Vida by Vinod Rastogi
3. Matri Bhoomi Ka Man by Hari Krishna
“Premi”
4. Sukhi Dali by Upendra Nath “Ashka”
5. Mahabharat Ki Ek Sanjh by Bharat
Bhushan Agrawal
6. Deepdan by Ram Kumar Verma

Sahitya Sangama: A collection of ICSE Short Stories & Poems. (Navakarnataka Publications,
Bengaluru)
(i) Short Stories:
1. Shivabhutiya Kathe by Panchatantra
3. Thalmege Olida Adrushta by N. Damodhara
6. Stainless Steel Patregalu by Vasudhendra
7. Kalavida by TA. RA. Subha Rao
8. Tollu Gatti by Kailasam
9. Kathegaara Manjanna by Kuvempu
10. Sevaashramada Linganna by Belagere Krishna Shastri
(ii) Poems:
1. Vachanagalu by Basavanna & Akkamahadevi
3. Tirukana Kanasu by Muppina Shadakshri
5. Negila Yogi by Kuvempu
6. Aru Hitavaru Ninage by Purandara Dasaru
7. Vashitha Vishwamitra Vivada by Ragayanka
8. Keladi Arasara Kathe by Lavani
9. Mankuhimmana Kagga by D.V. Gundappa
10. Mithile by S.R. Yekkundi
(iii) Novel: Natya Mayuri by Shri Sa. Shi. Marulayya
(iv) Drama: Hoovi by H.S. Venkatesh Murthy.

### Khasi (07)

(i) U Khain Bad Ka Bgen: by B.Chedrack
Jyrwa
(ii) Ka Ki Sngi U Syiem: by Dewi Singh
Khongdup.
1. U Phareng ha Lawkyntang
2. U Ksew, Ka Miaw bad u Tuta
3. U Sier Laplang bad u Shken
5. Ki Nongap masi u Syiem ha Sor
Shillong
6. U khun ka Nangdie phlang
(iii)Na Mihngi Sepngi: by Rev. H. Elias
1. Ka Thma Hidarpes
2. U Mahajon Ka Benis
3. Ka Khein-Kur Khein-kha
4. I Mei
5. Ka Shong jong ka Jingphohsniew
6. La Ka Lynti
(iv) Sawdong Ka Lynwiar Dpei: by P.G. Gatphoh
1. Ki Paro Ksiar
3. Ka Lukhimai

### Lepcha(20)

Recommended for background work: A Lepcha Grammar and Composition for Classes IX and X.
(i) Chhukpryom Pundor: Treasure of Prose, a Lepcha text book for Classes IX and X.
(ii) Chhukdong Pundor: Treasure of Poems, a Lepcha text book for Classes IX and X.
(iii) Sung Norzot: Treasure of Stories, a Lepcha Rapid Reader for Classes IX and X.

### Malayalam(08)

Sahitya Surabhi: A collection of ICSE Short Stories & Poems) (D.C. Books, Kottayam)

(i) Short Stories:
1. Manikkan by Lalithambika Antherjanam
2. Uthuppante Kinar by Karoor Neelakanta Pillai
4. Kattilekku Pokaruthe Kunje by Shehabudeen Poithumkadavu
5. Prakasham Parathunna Penkutty by T. Padmanabhan
7. Thahalseedarude Acha by Thakazhy Sivasankara Pillai
9. Model by Ponkunnam Varkey
10. Petta Vayar by C V Balakrishnan
(ii) Poems:
2. Puthen Kalavum Arivaalum by Edassery Govindan Nair
3. Karna Shoshana (1- 110 lines) by Ulloor
S Parameswarayyar
4. Karma Bhoomiyude Pinchukaal by Vallathol
5. Bhoomikkoru Charama Geetam by O N V
Kuruppu
6. Manikya Veena by Vennikkulam
8. Tachente Makal by Vijaya Lekshmi
9. Priyathame Prabhatame by K Ayyappa Panicker
10. Manaswani by Chagampuzha
(iii) Novel: Mayyazhippuzhayude Theerangalil by M Mukundan
(iv) Drama: Saketham by C N Sreekantan Nair

### Marathi(09)

(i) Kathakunj (Katha by Sankalan)
(ii) Kavyangan (Kavya by Sankalan)
(iv) Rangsparsh (Ekankika by Sankalan)

### Manipuri(18)

(i) Lamjing Lairik ( Meetei May ek Primer Classes IX & X).
(ii) Manipuri Sahitya Nachom ( Meetei Mayek or Roman Script Classes IX & X)
(iii) Manipuri Tengbang Sahitya (Meetei Mayek or Roman Script Classes IX & X)
(iv) Anouba Manipuri Grammar (Meetei Mayek or Roman Script Classes IX & X)

### Mizo(17)

Recommended for background work.
Mizo Grammar & Composition Part II by F. Lianhmingthanga and Lalthianghlima
(Hauhlira Press, Saron Veng, Aizawl).
(i) For Class IX
1. Mizo 9 by MBSE (revised)
(ii) For Class X –
1. Mizo – 9 by MBSE (revised)
2. Khawnglung Run by R. Lalrewna (Rapid Reader)

### Nepali(10)

(i) Short Stories
1. Aunthi by Achha Rai Rashik
3. Taar Chudieko Saarangi by Jasyonzon
Pyasi
4. Mrituko Mukhenji by Parsuram Roka
6. Jeodolash by Matilda Rai
7. Maachako Mol by Sivkumar Rai
8. Jyotibinako Ujyalo by Sanu Lama
9. Gariman by Indra Sundas
10.Jiwan Yatra by M.M. Gurung

(ii) Poems
1. Mritukamana Kehi Mera by Agamsing Giri
2. Man by Girmi Sherpa
3. Bolee by Tekdhoj Jimba
4. Natra Barbad Bhayo by Dharnidhar Koirala
6. Karma by Balkrishna Sam
7. Ram-Bharat Sambat by Bhanubhaktta
Acharya
8 Kaal Mahimaa by Lekhnath Paudyal
Deokota
10. Utsarga by Lakhi Devi Sundas
iii) Novel: Bhrammer by Rupnarayan Sinha
iv) Ekanki Kunj: A collection of ICSE One Act
Plays. (Gamma Publication, Darjeeling)
2. Tika by Mohan by Pukar
3. Ma Bhat Khanna by Ramlal Adhikari
4. Maag by Leela
5. Saahinu by Sanu Bhai Sharma
6. Shringkhala Bandane Chhanharu by Laxman Shreemal

### Odia(11)

Gyanjali : A collection of Short Stories & Poems. (Friends Publishers, Cuttack)
(i) Short Stories
1. Dhulia Baba by Fakir Mohan Senapati
3. Shikar by Bhagawati Charana
Panigrahi
4. Krupana by Mr. Manoj Das
5. Mukhagni by Lakshmi Chand
6. Nayanapura Express by Surendra Mohanty
7. Dimiri Phula by Akhila Mohan Pattnayak
8. Samantara Saralarekha by Bibhuti
Pattanayak
9. Neela Mastarani by Godabarish Mohapatra
10. Anguthi by Sachidananda Routray
(ii) Poems
1. Gandharira Ashirbada by Kalandi Charana Panigrahi
2. Kali Jai by Pandit Godabarish Mishra
3. Mahima by Swabhaba Kabi Gangadhara Meher
4. Banaphula Udyana Kusum by Utkala Bharati Kuntala Kumari Sabat
5. Garibara Durgastaba by Pandit Godabarish Mohapatra
6. Jagate Kebala by Kabisurya Baladeva Ratha
7. Grama Patha by Binod Chandra Nayak
9. Bandira Biraha Byatha by Pandit Gopabandhu Das
10. Khadyotika by Bidyut Prava Devi
(iii) Novel: ‘Aadoora Sakala by Prashant Mohanty
(iv) Ekakinka Chayan: A collection of ICSE One Act Plays(Friends Publishers, Cuttack)
1. Petu by Pranabandhu Kar
2. Rani Shuka Dei by Manoranjan Das
3. Bagha Sikara by Ranjit Pattnaik
4. Konarka by Bhanja Kishore Pattnayak
5. Ahuti by Kartik Chandra Rath
6. Aee Pataka Tale by Kulamani Mohapatra

### Punjabi(12)

Recommended grammar book in Punjabi

Shiromani Punjabi Vyakaran Ate Rachanawali
Kav by Katha Samvedna: A collection of Short Stories & Poems (Evergreen Publications, New Delhi)
(i) Short Stories
1. Pahuta Pandhi by Gurbax Singh
2. Bhatta by Sant Singh Sekhon
3. Zeenat Appa by Kartar Singh Duggal
4. Dharti Hethla Balad by Kulwant Singh Virk
5. Sanjhi Kandh by Santokh Singh Dheer
6. Saggi Phul by Gurdial Singh
7. Rub Te Ruttan by Dr. Dalip Kaur Tiwana
8. Baki Sab Sukh Saand Hai by Mohan Bhandari
9. Chandova by Kartar Singh Suri
10. Saheed by K.L. Garg
(ii) Poems
1. Sama by Bhai Veer Singh
2. Maa Da Dil by Firoz Din Sharaf
3. Mele Vich Jatt by Dhani Ram Chatrak
4. Chhatto Di Beri by Prof. Mohan Singh
5. Aaj Akhan Waris Shah Nu by Amrita Pritam
6. Jionde Bhagwan by Nand Lal Noorpuri
7. Rukh by Shiv Kumar Batalvi
8. Mera Bachpan by Harbhajan Singh
9. Nike Vade Dar by Jagtar
10. Hanera Jarega Kiven by Surjit Patar
(iii) Novel: Pataal De Githmuthiye by Jasbir Bhullar
(iv) Manch Mehak by A collection of ICSE One
Act Plays (Evergreen Publications, New Delhi)
1. Suhag by I.C. Nanda
2. Dr. Palta by Balwant Gargi
3. Dushman by Gurcharan Singh Jasuja
4. Parat Auan Tak by Satish Verma
5. Phullan Nu Kitaban Vich Na Rakho by Pali Bhupinder

### Sanskrit(19)

(i) Sanskrit Vani Book 4 ( for C lass IX) by H.D. V ijayshri and Mrs. S. Bolar
(ii) Sanskrit Vani Book 5 ( for C lass X) by H.D. Vijayshri and Mrs. S. Bolar

### Tamil(13)

(i) Rajaraja Cholan (Drama) by R. Ramanathan
(ii) Veerapandiya Kattabhomman (Novel) by K. Jeeva B harathi
(iii)Charitra Sambavangal (Historical Essays) by “ Vaandumama” V . K rishnamoorthy

### Tangkhul(47)

(i)Tangkhul Tuitam K achiko, Class IX published by Luitham Press, Ukhrul (2006).
(ii) Tangkhul Tuitam K athara, Class X published by Luitham Press, Ukhrul (2006).
(iii)Kathaka Tangkhul Tuitam (Classes IX and X published by L uitham P ress, Ukhrul(2006).

### Telugu(14)

(i) Poems
1. Vidura Neethi by Tikkana Somayaji
2. Sneha Dharmam by Bammera Pothana
3. Atidhi Sevanamu by Sri Krishna Devarayalu
4. Paarijatha Prasoonamu by Nandi Thimmana
6. Sathaka Manjari – Narasima Sathakam by Seshappa Kavi (26, 38, 39, 54 poems)
& Sri Kalahasthiswara Sathakam by
Dhurjati (12,13,27,28 poems)
7. Krushivaludu by Duvvuri Ramireddy
8. Manavathvam by Nandur
Ramakrishnamacharyulu
9. Mathru Mandiram by Devulapalli
Krishna Shastri
10. Nenantanu by Dasarathi Krishnamacharyulu
(ii) Short Stories
1. Indra Dyumuni Samudra Prayaanam by Madhira Subbanna Deekshitulu
3. Taapi Mesthri by Shri Paada Subramanya Sastri
4. Appudu Putti Vunte by Devulapalli Krishna Sastry
5. Oka Cheema Katha by Dr. Raavuri Bharadwaja
6. Swatantrodyama Nepadhyamulo Prabhodha Geetalu by Raavi Bharathi
8. Bhasha Saili- Rachana Bedhalu by Chekuri Ramarao
9. .Riktha Hasthamulu by Vidya Prakasananda Giri Swamy
10. Samskruti by Acharya Khandavalli Lakshmi Ranjanam
(iii) Novel: Ganapathi – Chilakamarthi by Lakshmi Narasimham
(iv) Drama: Vishnu Sharma English Chaduvu by C.S. Rao

### Tenyidie(41)

(i) Neteya
(ii) Noudo Dze by Dino and Viswedel
(iii)Uca –53 by Shurhozelie

### Urdu(16)

Lazawal M uraqqe – A collection of ICSE Short Stories and Poems / Gazals
(i) Short Stories
1. Ibadat by Munshi Prem Chand
2. Bhola by Rajendar Singh Bedi
3. Bachpan by Ismath Choghtai
4. Pital Ka Ghanta by Qazi Abdus Sattar
5. Manzoor by Saadat Hasan Manto
6. Allah De Band Le by Razia Sajjad Zaheer
7. Aakhri Qadam by Dr. Zakir Hussain
8. Khadar Ka Kafan by Khaja Amed Abbas
10. Ek Aur Shrawan Kumar by Salam Bin Razzaq
(ii) Poetry – Poems and Ghazals
1. Piya Baaj Piala Piya Jaye na (Ghazal) by Mohd Quli Qutub Shah
2. Faqeerana Ayee Sada Kar Chaley(Ghazal) by Mir Taqi Mir
3. Dard Minnat Kashey Dawa Na Huwa(Ghazal) by Mirza Ghalib
4. Phir Chedi Raat Baat Phooloon Ki (Ghazal) by Makhdoom Mohiuddin
5. Justujoo Jis Ki Thi…(Ghazal) by Sher e Yaar
6. Who To Khushboo Hai…(Ghazal) by Parveen Shakir
7. Kaljugh (Poem) by Nazeer Akbar Aabadi
8. Chand Aur Tare (Poem) by Sir Mohd Iqbal
9. Aawo Ke Koyi Khawaab Bunien(Poem) by Sahil Ludhiyanavi
10. Aurat (Poem) by Kaife Azmi
(iii) Novel: Nusuh Ka Khawaab by Nazeer Ahamed
(iv) Drama: Darwaze Khol Do by Krishan Chander

Modern Foreign Languages

### French(27)

Teaching and study resource books:

### German(28)

Teaching and study resource books:
(i) For Class IX Planet 1 (Textbook and Workbook)

### Spanish(36)

Teaching and study resource books:
(i) Espanol Sin Fronteras Bk 2
(ii) Workbook Nuevo Ven Bk 2
(iii) Pasaporte Bk 2

### FAQs on ICSE Books

Question 1.

Which Books are used in ICSE Board?

There are several books that one can follow in ICSE Board. Some of the popular ones are

• Concise series by Selina Publications
• Candid ICSE books
• S.Chand Publications
• Understanding ICSE Mathematics series by M.L. Aggarwal
• Together With series by Rachna Sagar publications
• APC Mathematics
• RD Sharma

You can even refer to the ICSE Books listed in this article to know the subjectwise study material.

Question 2.

What are ICSE Reference Books?

ICSE Reference Books are the Textbooks as per the CISCE Curriculum that gives you insight on syllabus topics.

Question 3.

Where can I buy ICSE Books Online?

There are few publishers who publish ICSE Books based on the Prescribed Syllabus and you can buy them from various websites that sell books.

### Final Words

We believe the knowledge shared above regarding ICSE Books Subjectwise has shed some light on you. If you are having any other queries related to the recommended books for ICSE then you can drop us a comment and let us know. We will strive to help you at the earliest possible.

## Selina Concise Mathematics Class 10 ICSE Solutions Chapter 1 GST (Goods and Services Tax)

Selina Publishers Concise Mathematics Class 10 ICSE Solutions Chapter 1 GST (Goods and Services Tax)

### GST Exercise 1A – Selina Concise Mathematics Class 10 ICSE Solutions

Question 1.
For the following transaction within Delhi, fill in the blanks to find the amount of bill :
MRP = Rs. 12,000, Discount % = 30%, GST = 18%
Discount =
Selling price (discounted value) =
CGST =
SGST =
IGST =
Amount of Bill =
Solution:
MRP = Rs. 12,000, Discount % = 30%, GST= 18%
Discount = 30% of 12,000= $$\frac{30}{100}$$ × 12000 = Rs. 3600
Selling price (discounted value) = 12000 – 3600
= Rs. 8400
CGST= 9% of 8400 = Rs. 756
SGST= 9% of 8400 = Rs. 756
IGST= 0
Amount of Bill = Selling price + CGST + SGST = 8400 + 756 + 756 = Rs. 9912

Question 2.
For the following transaction from Delhi to Jaipur, fill in the blanks to find the amount of bill :
MRP = Rs. 50,000, Discount % = 20%, GST = 28%
Discount =
Selling price (discounted value) =
CGST =
SGST =
IGST =
Amount of Bill =
Solution:
MRP = Rs. 50,000, Discount % = 20%, GST= 28%
Discount = 20% of 50,000 = $$\frac{20}{100}$$ × 50,000 = Rs. 10,000
Selling price (discounted value) = 50,000 – 10,000
= Rs. 40,000
CGST = 0
SGST = 0
IGST = 28% of 40,000 = $$\frac{28}{100}$$ × 40,000 = Rs. 11,200
Amount of Bill = Selling price + IGST
= 40,000 + 11,200
= Rs. 51,200

Question 3.
A computer mechanic in Delhi charges repairing cost from five different persons A, B, C, D and E with certain discounts. The repairing costs and the corresponding discounts are as given below :

If the rate of GST is 18%, find the total money (including GST) received by the mechanic.
Solution:
Name of the person Repairing cost (in Rs.) Discount % Discount Selling price CGST (9%) SGST (9%)

The total money (including GST) received by the mechanic is 18,820 + 1693.8 + 1693.8
= Rs. 22,207.6

Question 4.
Find the amount of bill for the following intra-state transaction of goods/services. The GST rate is 5%.

Solution:

Amount of bill = Selling price + GST
= 10,290 + 257.25 + 257.25
= Rs. 10,804.5

Question 5.
Find the amount of bill for the following inter-state transaction of goods/services. The GST rate is 18%.

Solution:

Amount of bill = Selling price + CGST + SGST
= 44,210 + 3978.9 + 3978.9
= Rs. 52,167.8

Question 6.
Find the amount of bill for the following intra-state transaction of goods/services.

Solution:

Amount of bill = Selling price + CGST + SGST
= 37,850 + 2785 + 2785
= Rs. 43,420

Question 7.
Find the amount of bill for the following inter-state transaction of goods/services.

Solution:

Amount of bill = Selling price + GST
= 37,850 + 5570
= Rs. 43,420

Question 8.
A dealer in Mumbai supplied an item at the following prices to a dealer in Delhi. Find the total amount of the bill.

Solution:

Amount of bill = Selling price + IGST
= 17,710 + 3187.8
= Rs. 20,897.8

Question 9.
National Trading Company, Meerut (UP) made the supply of the following goods/services to Samarth Traders, Noida (UP). Find the total amount of bill if the rate of GST = 12%

Solution:

Amount of bill = Selling price + SGST + CGST
= 17,220 + 2066.4
= Rs. 19,286.4

Question 10.
M/s Ram Traders, Delhi, provided the following services to M/s Geeta Trading Company in Agra (UP). Find the amount of bill :

Solution:

Amount of bill = Selling price + IGST
= 18,600 + 2007.2
= Rs. 20,607.2

Question 11.
For the following, find the amount of bill data :

Solution:

Amount of bill = Selling price + GST
= 15,168 + 2634.24
= Rs. 17,802.24

Question 12.
The tax invoice of a telecom service in Meerut shows cost of services provided by it as Rs. 750. If the GST rate is 18%, find the amount of the bill.
Solution:
According to the question,
GST = 18% of 750
= $$\frac{18}{100}$$ × 750 = Rs. 135
The amount of bill = 750 + 135 = Rs. 885

Question 13.
Mr. Pankaj took Health Insurance Policy for his family and paid Rs. 900 as SGST. Find the total annual premium paid by him for this policy, rate of GST being 18%.
Solution:
Let the total annual premium paid by Mr. Pankaj be Rs. x. According to the question, 18% of x= SGST + CGST 18% of x= 1800 SGST= CGST $$\frac{18}{100}$$ × x = 1800
x = Rs. 10,000

Question 14.
Mr. Malik went on a tour to Goa. He took a room in a hotel for two days at the rate of Rs. 5000 per day. On the same day, his friend John also joined him. Hotel provided an extra bed charging Rs. 1000 per day for the bed. How much GST, at the rate of 28% is charged by the hotel in the bill to Mr. Malik for both the days?
Solution:
According to the question,
The amount of bill = 5000 × 2 + 1000 + 1000
= 10,000 + 2000
= Rs. 12,000
GST= 28% of 12,000
= $$\frac{28}{100}$$ × 12,000 = Rs. 3360
GST charged by Mr. Malik Rs. 3360.

Question 15.
Asharaf went to see a movie. He wanted to purchase a movie ticket for Rs. 80. As the ticket for Rs. 80 was not available, he purchased a ticket for Rs. 120 of upper class. How much extra GST did he pay for the ticket? (GST for a ticket below Rs. 100 is 18% and GST for a ticket above Rs. 100 is 28%)
Solution:
According to the question,
GST on ticket of Rs. 80 = 18% of 80= $$\frac{18}{100}$$ × 80 = Rs. 14.40
GST on ticket of Rs. 120 = 28% of 120= $$\frac{18}{100}$$ × 120 = Rs. 33.60
Difference between both GST
= 33.60 – 14.40
= Rs. 19.20

### GST Exercise 1B- Selina Concise Mathematics Class 10 ICSE Solutions

Question 1.
Fill in the blanks :
When the goods/services are sold for Rs. 15,000 under intra-state transaction from station A to station B and the rate of GST is 12%.
As per GST System
S.P. at station A =
CGST = 6% of 15,000 =
SGST = 6% of 15,000 =
C.P. at station B =
If profit = Rs. 5000
S.P. at station B =
Now the same goods/services are moved under inter-state transaction from station B to station C and the rate of tax is 12%.
GST =
C.P. at station C =
Solution:
When the goods/services are sold for Rs. 15,000 under intra-state transaction from station A to station B and the rate of GST is 12%.
As per GST System
S.P. at station A = Rs. 15,000
CGST = 6% of 15,000 = Rs. 900
SGST = 6% of 15,000 = Rs. 900
C.P. at station B = Rs. 15,000
If profit = Rs. 5000
S.P. at station B = 15,000 + 5000
= Rs. 20,000
Now the same goods/services are moved under inter-state transaction from station B to station C and the b rate of tax is 12%.
GST = 12% of 20,000
= Rs. 2400
C.P. at station C = Rs. 20,000

Question 2.
Goods/services are sold from Agra (U.P.) to Kanpur (U.P.) for Rs. 20,000 and then from Kanpur to Jaipur (Rajasthan). If the rate of GST is 18% and the profit made at Kanpur is Rs. 5000, find:

• the net GST payable by the dealer at Kanpur.
• the cost of goods/services at Jaipur.

Solution:
When the product is sold from Agra to Kanpur (intra-state transaction)
For the dealer in Agra :
S. P. in Agra = Rs. 20,000
CGST = 9% of Rs. 20,000 = $$\frac{9}{100}$$ × 20,000 = 1800
SGST = 9% of Rs. 20,000 = $$\frac{9}{100}$$ × 20,000 = 1800
When product is sold from Kanpur to Jaipur (inter-state transaction)
For the dealer in Kanpur
Input-tax credit = 1800 + 1800 = Rs. 3600
C. P. = Rs. 20,000 and Profit = Rs. 5000
S.P. = 20,000 + 5000 = Rs. 25,000
IGST = 18% of 25,000 = Rs. 4500

Net GST paid by the dealer at Kanpur
= Output GST – Input GST
= 4500 – 3600
= Rs. 900

The cost of goods/services at Jaipur
= S. P. in Agra + IGST
= 25,000 + 18% of 25000
= 25,000 + 4500
= Rs. 29,500

Question 3.
Goods/services are sold from Kota (Rajasthan) to Mumbai for Rs. 20,000 and then from Mumbai to Pune. If the rate of GST is 12% and the profit made at Mumbai is Rs. 5000; find the net GST paid at Pune, if the dealer at Pune is the end-user.
Solution:
For the dealer in Mumbai (inter-state transaction)
CP = Rs. 20,000
IGST = 12% of Rs. 20,000 = $$\frac{12}{100}$$ × 20,000 = Rs. 2400
Profit = Rs. 5000
SP = Rs. 25,000
For the dealer in Pune (intra-state transaction)
CP = Rs. 25,000
CGST = 6% of 25,000 = Rs. 1500
SGST = 6% of 25,000 = Rs. 1500
GST payable by the end user at Pune = 1500 + 1500= Rs. 3000

Question 4.
A is a dealer in Banaras (U.P.). he supplies goods/services worth Rs. 8000 to a dealer B in Agra (U.P.). Dealer B, in turn, supplies the same goods/services to dealer C in Patna (Bihar) at a profit of Rs. 1200. Find the input and output taxes for the dealer C under GST system; if the rate of GST is 18% and C does not sell his goods/services further.
Solution:
For the dealer A (intra-state transaction)
SP= Rs. 8,000

For the dealer B (intra-state transaction)
CP = Rs. 8,000
CGST = 9% of 8,000 = Rs. 720
SGST = 9% of 8,000 = Rs. 720
Profit = Rs. 1,200
SP = Rs. 9,200

For the dealer C (inter-state transaction)
CP = Rs. 9,200
IGST = 18 % of Rs. 9,200 = $$\frac{18}{100}$$ × 9,200 = Rs. 1656
Input Tax = Rs. 1,656
Since, the dealer in Patna does not sell the product.
Output GST (tax on sale) = Rs. 0

Question 5.
A is a dealer in Meerut (U.P.). He supplies goods/services, worth Rs. 15,000 to a dealer B in Ratlam (M.P.). Dealer B, in turn, supplies the same goods/services to dealer C in Jabalpur (M.P.) at a profit of Rs. 3000. If rate of tax (under GST system) is 18%, find

• The cost of goods/services to the dealer C in Jabalpur.
• Net tax payable by dealer B.

Solution:
For A (case of inter-state transaction)
S.P. in Meerut = Rs. 15,000

For B (case of inter-state transaction)
C.P. = Rs. 15,000
IGST = 18% of 15,000 = $$\frac{18}{100}$$ × 15,000 = Rs. 2700
Output tax for B = Rs. 2,700
C.P. in Ratlam = Rs. 2700 and profit = Rs. 3000
S.P. in Ratlam = 15,000 + 3000 = Rs. 18,000
Output tax for B =
For C (case of intra-state transaction)
C.P. = Rs. 18,000
CGST = 9% of 18,000 = $$\frac{9}{100}$$ × 18,000 = Rs. 1620
SGST = $$\frac{9}{100}$$ × 18,000 = Rs. 1620
Net GST payable by the dealer B
= Output tax – Input tax
= 1620 + 1620 – 2700
= Rs. 540
C.P. for the dealer C in Jabalpur
= S.P. for the dealer in Ratlam + GST
= 18,000 + 1620 + 1620
= Rs. 21,240

Question 6.
A dealer X in Hapur (U.P.) supplies goods/services, worth Rs. 50,000 to some other dealer Y in the same city. Now the dealer Y supplies the same goods/services to dealer Z in Calcutta at a profit of Rs. 20,000. Find

• Output and input taxes for the dealer Y
• Net GST payable by dealer Y.

The rate of GST at each stage is 28%
Solution:
For the dealer X (intra-state transaction)
SP= Rs. 50,000

For the dealer Y (intra-state transaction)
CP = Rs. 50,000
CGST = 14% of 50,000= Rs. 7,000
SGST = 14% of 50,000= Rs. 7,000
Input tax for dealer Y = Rs. 14,000
Profit = Rs. 20,000
SP = Rs. 70,000

For the dealer Z (inter-state transaction)
CP = Rs. 70,000
IGST = 28 % of Rs. 70,000 = $$\frac{28}{100}$$ × 70,000 = Rs. 19,600
∴ Input Tax = Rs. 19,600 which is the output tax for dealer Y.

Net GST payable for Y
= Output tax for Y – Input tax for Y
= 19,600 – 14,000
= Rs. 5600

Question 7.
Consultancy services, worth Rs. 50,000, are transferred from Delhi to Calcutta at the rate of GST 18% and then from Calcutta toNainital (with profit = Rs. 20,000) at the same rate of GST. Find the output tax at

• Delhi
• Calcutta
• Nainital

Solution:
Output tax in Delhi (interstate) :
IGST = 9% of 50,000 = Rs. 9000
Output tax in Delhi = Rs. 9000

Output tax in Calcutta :
C.P. in Calcutta = Rs. 50,000 and Profit
= Rs. 20,000
S.P. in Calcutta = 50,000 + 20,000
= Rs. 70,000
IGST = 18% of 70,000 = Rs. 12,600
Output tax in Calcutta = Rs. 12,600
Since, the dealer in Nainital does not sell the product.
Output GST (tax on sale) = Rs. 0

Question 8.
For a dealer A, the list price of an article is Rs. 9000, which he sells to dealer B at some lower price. Further, dealer B sells the same article to a customer at its list price. If the rate of GST is 18% and dealer B paid a tax, under GST, equal to Rs. 324 to the government, find the amount (inclusive of GST) paid by dealer B.
Solution:
Let A sells to dealer B at Rs. x lower price.
According to the question,
Net Tax paid by dealer B is
⇒ Out put tax – Input Tax = Rs. 324
⇒ 18% of 9000 – 18% of (9000 – x) = 324
⇒ 1620 – 1620 + 18% of x = 324
⇒ 18% of x = 324
⇒ x= 1800
Hence, selling price of B = 9000 – 1800 = Rs. 7200
The amount (inclusive of GST) paid by dealer B
= 7200 + 18% of 7200
= 7200 + 1296
= Rs. 8496

Question 9.
The marked price of an article is Rs. 6000. A wholesaler sells it to a dealer at 20% discount. The dealer further sells the article to a customer at a discount of 10% on the marked price. If the rate of GST at each stage is 18%, find the amount of tax (under GST) paid by the dealer to the government.
Solution:
Initial marked price by manufacturer A is Rs. 6000
B bought the T.V. at a discount of 20%.
Cost price of B = 80% of 6000 = Rs. 4800 ….(i)
GST paid by B for purchase = 18% of 4800 = Rs. 864 ….(ii)
B sells T.V. at discount of 10% of market Price
Selling price for B = 6000 – 10% of 6000 = Rs. 5400 …(iii)
GST charged by B on selling of T.V. = 18% of 5400 = Rs. 972 …(iv)
GST paid by B to the government
= GST charged on selling price – GST paid against purchase price
= 972 – 864
= Rs. 108

Question 10.
A is a manufacturer of T.V. sets in Delhi. He manufacturers a particular brand of T.V. set and marks it at Rs. 75,000. He then sells this T.V. set to a wholesaler B in Punjab at a discount of 30%. The wholesaler B raises the marked price of the T.V. set bought by 30% and then sells it to dealer C in Delhi. If the rate of GST = 5% find tax (under GST) paid by wholesaler B to the government.
Solution:
Initial marked price by manufacturer A is Rs. 75,000
B bought the T.V. at a discount of 30%.
Cost price of B = 70% of 75,000 = Rs. 52,500 ….(i)
GST paid by B for purchase = 5% of 52,500 = Rs. 2625 ….(ii)
B sells T.V. by increasing marked price by 30%.
Selling price for B = 75,000 + 30% of 75,000 = Rs. 97,500 …(iii)
GST charged by B on selling of T.V. = 5% of 97,500
= Rs. 4875 …(iv)
GST paid by B to the government
= GST charged on selling price – GST paid against purchase price
= 4875 – 2625
= Rs. 2250

Question 11.
For a trader, marked price of a refrigerator = Rs. 15,680 inclusive of GST at the rate of 12% on the marked price. Gagan, a customer for this refrigerator, asks the trader to reduce the marked price of the refrigerator to such extend that its reduced price plus GST on it is equal to marked price of the refrigerator. Find the required reduction.
Solution:
Let the marked price be Rs. x.
x + 12% of x = 15,680
1.12x = 15,680
x = Rs. 14,000
Initial marked price = Rs. 14,000
Let Gagan asked for priced reduction of Rs. y.
New price = 14,000 – y
GST on new price = 12% of (14,000 – y)
According to the question,
14,000 – y + 0.12(14,000 – y) = 14,000
-1.12y + 1680 = 0
y = 1500
Required reduction in price is Rs. 1500.

## Selina Concise Mathematics Class 10 ICSE Solutions Banking (Recurring Deposit Accounts)

Selina Publishers Concise Mathematics Class 10 ICSE Solutions Chapter 2 Banking (Recurring Deposit Accounts)

### Banking (Recurring Deposit Accounts) Exercise 2A – Selina Concise Mathematics Class 10 ICSE Solutions

Question 1.
Manish opens a Recurring Deposit Account with the Bank of Rajasthan and deposits ₹ 600 per month for 20 months. Calculate the maturity value of this account, if the bank pays interest at the rate of 10% per annum.
Solution:
Installment per month(P) = ₹ 600
Number of months(n) = 20
Rate of interest(r) = 10% p.a.

The amount that Manish will get at the time of maturity
= ₹ (600×20) + ₹ 1,050
= ₹ 12,000 + ₹ 1,050
= ₹ 13,050

Question 2.
Mrs. Mathew opened a Recurring Deposit Account in a certain bank and deposited ₹ 640 per month for 4 ½ years. Find the maturity value of this account, if the bank pays interest at the rate of 12% per year.
Solution:
Installment per month(P) = ₹ 640
Number of months(n) = 54
Rate of interest(r)= 12% p.a.

The amount that Manish will get at the time of maturity
= ₹ (640×54)+ ₹ 9,504
= ₹ 34,560 + ₹ 9,504
= ₹ 44,064

Question 3.
Each of A and B both opened recurring deposit accounts in a bank. If A deposited ₹ 1,200 per month for 3 years and B deposited ₹ 1,500 per month for 2 ½ years; find, on maturity, who will get more amount and by how much? The rate of interest paid by the bank is 10% per annum.
Solution:
For A
Installment per month(P) = ₹ 1,200
Number of months(n) = 36
Rate of interest(r) = 10% p.a.

The amount that A will get at the time of maturity
= ₹ (1,200×36) + ₹ 6,660
= ₹ 43,200 + ₹ 6,660
= ₹ 49,860
For B
Instalment per month(P) = ₹ 1,500
Number of months(n) = 30
Rate of interest(r) = 10% p.a.

The amount that B will get at the time of maturity
= ₹ (1,500×30) + ₹ 5,812.50
= ₹ 45,000 + ₹ 5,812.50
= ₹ 50,812.50
Difference between both amounts = ₹ 50,812.50 – ₹ 49,860
= ₹ 952.50
Then B will get more money than A by ₹ 952.50.

Question 4.
Ashish deposits a certain sum of money every month is a Recurring Deposit Account for a period of 12 months. If the bank pays interest at the rate of 11% p.a. and Ashish gets ₹ 12,715 as the maturity value of this account, what sum of money did money did he pay every month?
Solution:
Let Installment per month(P) = ₹ y
Number of months(n) = 12
Rate of interest(r) = 11% p.a.

Maturity value = ₹ (y × 12) + ₹ 0.715y = ₹ 12.715y
Given maturity value = ₹ 12,715
Then ₹ 12.715y = ₹ 12,715

Question 5.
A man has a Recurring Deposit Account in a bank for 3 ½ years. If the rate of interest is 12% per annum and the man gets ₹ 10,206 on maturity, find the value of monthly instalments.
Solution:
Let Installment per month(P) = ₹ y
Number of months(n) = 42
Rate of interest(r) = 12% p.a.

Maturity value= ₹ (y × 42) + ₹ 9.03y= ₹ 51.03y
Given maturity value = ₹ 10,206
Then ₹ 51.03y = ₹ 10206

Question 6.
(i) Puneet has a Recurring Deposit Account in the Bank of Baroda and deposits ₹ 140 per month for 4 years. If he gets ₹ 8,092 on maturity, find the rate of interest given by the bank.
(ii) David opened a Recurring Deposit Account in a bank and deposited ₹ 300 per month for two years. If he received ₹ 7,725 at the time of maturity, find the rate of interest per annum.
Solution:
(a)
Installment per month(P) = ₹ 140
Number of months(n) = 48
Let rate of interest(r) = r% p.a.

Maturity value= ₹ (140 × 48) + ₹ (137.20)r
Given maturity value = ₹ 8,092
Then ₹ (140 × 48) + ₹ (137.20)r = ₹ 8,092
⇒ 137.20r = ₹ 8,092 – ₹ 6,720

(b)
Instalment per month(P) = ₹ 300
Number of months(n) = 24
Let rate of interest(r)= r% p.a.

Maturity value = ₹ (300 × 24) + ₹ (75)r
Given maturity value = ₹ 7,725
Then ₹ (300 × 24) + ₹ (75)r = ₹ 7,725
⇒ 75 r = ₹ 7,725 – ₹ 7,200

Question 7.
Amit deposited ₹ 150 per month in a bank for 8 months under the Recurring Deposit Scheme. What will be the maturity value of his deposits, if the rate of interest is 8% per annum and interest is calculated at the end of every month?
Solution:
Installment per month(P) = ₹ 150
Number of months(n) = 8
Rate of interest(r) = 8% p.a.

The amount that Manish will get at the time of maturity
= ₹ (150 × 8) + ₹ 36
= ₹ 1,200 + ₹ 36
= ₹ 1,236

Question 8.
Mrs. Geeta deposited ₹ 350 per month in a bank for 1 year and 3 months under the Recurring Deposit Scheme. If the maturity value of her deposits is ₹ 5,565; find the rate of interest per annum.
Solution:
Installment per month(P) = ₹ 350
Number of months(n) = 15
Let rate of interest(r)= r% p.a.

Maturity value= ₹ (350 × 15) + ₹ (35)r
Given maturity value = ₹ 5,565
Then ₹ (350 × 15) + ₹ (35)r = ₹ 5,565
⇒ 35r = ₹ 5,565 – ₹ 5,250

Question 9.
A recurring deposit account of ₹ 1,200 per month has a maturity value of ₹ 12,440. If the rate of interest is 8% and the interest is calculated at the end of every month; find the time (in months) of this Recurring Deposit Account.
Solution:
Installment per month(P) = ₹ 1,200
Number of months(n) = n
Let rate of interest(r) = 8% p.a.

Maturity value = ₹ (1,200 × n) + ₹ 4n(n+1) = ₹ (1200n+4n2+4n)
Given maturity value= ₹ 12,440
Then 1200n+4n2+4n = 12,440

Then number of months = 10

Question 10.
Mr. Gulati has a Recurring Deposit Account of ₹ 300 per month. If the rate of interest is 12% and the maturity value of this account is ₹ 8,100; find the time (in years) of this Recurring Deposit Account.
Solution:
Installment per month(P) = ₹ 300
Number of months(n) = n
Let rate of interest(r)= 12% p.a.

Maturity value= ₹ (300 × n)+ ₹ 1.5n(n+1)
= ₹ (300n+1.5n2+1.5n)
Given maturity value= ₹ 8,100
Then 300n+1.5n2+1.5n = 8,100

Then time = 2 years.

Question 11.
Mr. Gupta opened a recurring deposit account in a bank. He deposited ₹ 2,500 per month for two years. At the time of maturity he got ₹ 67,500. Find:
(i) the total interest earned by Mr. Gupta
(ii) the rate of interest per annum.
Solution:
(i)
Maturity value = ₹ 67,500
Money deposited = ₹ 2,500 × 24= ₹ 60,000
Then total interest earned = ₹ 67,500 – ₹ 60,000 = ₹ 7,500 Ans.
(ii)
Installment per month(P) = ₹ 2,500
Number of months(n) = 24
Let rate of interest(r)= r% p.a.

### Banking (Recurring Deposit Accounts) Exercise 2B- Selina Concise Mathematics Class 10 ICSE Solutions

Question 1.
Pramod deposits ₹ 600 per month in a Recurring Deposit Account for 4 years. If the rate of interest is 8% per year; calculate the maturity value of his account.
Solution:
Installment per month(P) = ₹ 600
Number of months(n) = 48
Rate of interest(r)= 8% p.a.

The amount that Manish will get at the time of maturity
= ₹ (600 × 48) + ₹ 4,704
= ₹ 28,800 + ₹ 4,704
= ₹ 33,504

Question 2.
Ritu has a Recurring Deposit Account in a bank and deposits ₹ 80 per month for 18 months. Find the rate of interest paid by the bank if the maturity value of account is ₹ 1,554.
Solution:
Installment per month(P) = ₹ 80
Number of months(n) = 18
Let rate of interest(r) = r% p.a.

Maturity value = ₹ (80 × 18) + ₹ (11.4r)
Given maturity value = ₹ 1,554
Then ₹ (80 × 18 ) + ₹ (11.4r) = ₹ 1,554
⇒ 11.4r  = ₹ 1,554 – ₹ 1,440

Question 3.
The maturity value of a R.D. Account is ₹ 16,176. If the monthly installment is ₹ 400 and the rate of interest is 8%; find the time (period) of this R.D Account.
Solution:
Installment per month(P) = ₹ 400
Number of months(n) = n
Let rate of interest(r)= 8% p.a.

⇒ 1200n +4n2+4n= ₹ 48,528
⇒ 4n2+1204n = ₹ 48,528
⇒ n2+301n – 12132= 0
⇒ (n+337)(n-36)=0
⇒ n = -337 or n=36
Then number of months = 36 months = 3 years

Question 4.
Mr. Bajaj needs ₹ 30,000 after 2 years. What least money (in multiple of 5) must he deposit every month in a recurring deposit account to get required money after 2 years, the rate of interest being 8% p.a.?
Solution:
Let installment per month = ₹ P
Number of months(n) = 24
Rate of interest = 8% p.a.

Maturity value = ₹ (P × 24)+ ₹ 2P = ₹ 26P
Given maturity value = ₹ 30,000

Question 5.
Rishabh has recurring deposit account in a post office for 3 years at 8% p.a. simple interest. If he gets ₹ 9,990 as interest at the time of maturity, find:
(i) The monthly installment.
(ii) The amount of maturity.
Solution:
Let Installment per month = ₹ P
Number of months(n) = 36
Rate of interest(r)= 8% p.a.

Given interest = ₹ 9,990

(ii) Maturity value = ₹ (2,250 × 36) + ₹ 9,990 = ₹ 90,990

Question 6.
Gopal has a cumulative deposit account and deposits ₹ 900 per month for a period of 4 years he gets ₹ 52,020 at the time of maturity, find the rate of interest.
Solution:
Installment per month(P) = ₹ 900
Number of months(n) = 48
Let rate of interest(r)= r% p.a.

Maturity value= ₹ (900 × 48) + ₹ (882)r
Given maturity value = ₹ 52,020
Then ₹ (900 × 48) + ₹ (882)r = ₹ 52,020
⇒ 882r = ₹ 52,020 – ₹ 43,200

Question 7.
Deepa has a 4-year recurring deposit account in a bank and deposits ₹ 1,800 per month. If she gets ₹ 1,08,450 at the time of maturity, find the rate of interest.
Solution:
Installment per month(P) = ₹ 1,800
Number of months(n) = 48
Let rate of interest(r)= r% p.a.

Maturity value = ₹ (1,800 x 48) + ₹ (1,764)r
Given maturity value = ₹ 1,08,450
Then ₹ (1,800 x 48) + ₹ (1764)r = ₹ 1,08,450
⇒ 1764r = ₹ 1,08,450 – ₹ 86,400

Question 8.
Mr. Britto deposits a certain sum of money each month in a Recurring Deposit Account of a bank. If the rate of interest is of 8% per annum and Mr. Britto gets Rs. 8,088 from the bank after 3 years, find the value of his monthly instalment.
Solution:

Question 9.
Shahrukh opened a Recurring Deposit Acoount in a bank and deposited Rs. 800 per month for 1 $$\frac { 1 }{ 2 }$$ years. If he received Rs. 15,084 at the time of maturity, find the rate of interest per annum.
Solution:

Question 10.
Katrina opened a recurring deposit account with a Nationalised Bank for a period of 2 years. If the bank pays interest at the rate of 6% per annum and the monthly installment is ₹ 1,000, find the :
(i) interest earned in 2 years
(ii) maturity value
Solution:

Question 11.
Mohan has a recurring deposit account in a bank for 2 years at 6% p.a. simple interest. If he gets Rs. 1200 as interest at the time of maturity, find
(i) the monthly installment
(ii) the amount of maturity
Solution:
Interest, I = Rs. 1,200
Time, n = 2 years = 2 × 12 = 24 months
Rate, r = 6%
(i) To find: Monthly instalment, P
Now,

So, the monthly instalment is Rs. 800.

(ii) Total sum deposited = P × n = Rs. 800 × 24 = Rs. 19,200
∴ Amount of maturity = Total sum deposited + Interest on it
= Rs. (19,200 + 1,200)
= Rs. 20,400

Question 11.
Peter has a recurring deposit account in Punjab National Bank at Sadar Bazar, Delhi for 4 years at 10% p.a. He will get ₹ 6,370 as interest on maturity. Find :
(i) monthlyinstallment,
(ii) the maturity value of the account.
Solution:

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## Selina Concise Mathematics Class 10 ICSE Solutions Quadratic Equations

Selina Publishers Concise Mathematics Class 10 ICSE Solutions Chapter 5 Quadratic Equations

### Quadratic Equations Exercise 5A – Selina Concise Mathematics Class 10 ICSE Solutions

Find which of the following equations are quadratic:

Solution 1(i)
(3x – 1)2 = 5(x + 8)
⇒ (9x2 – 6x + 1) = 5x + 40
⇒ 9x2 – 11x – 39 =0; which is of the form ax2 + bx + c = 0.
∴ Given equation is a quadratic equation.

Solution 1(ii)
5x2 – 8x = -3(7 – 2x)
⇒ 5x2 – 8x = 6x – 21
⇒ 5x2 – 14x + 21 =0; which is of the form ax2 + bx + c = 0.
∴ Given equation is a quadratic equation.

Solution 1(iii)
(x – 4)(3x + 1) = (3x – 1)(x +2)
⇒ 3x2 + x – 12x – 4 = 3x2 + 6x – x – 2
⇒ 16x + 2 =0; which is not of the form ax2 + bx + c = 0.
∴ Given equation is not a quadratic equation.

Solution 1(iv)
x2 + 5x – 5 = (x – 3)2
⇒ x2 + 5x – 5 = x2 – 6x + 9
⇒ 11x – 14 =0; which is not of the form ax2 + bx + c = 0.
∴ Given equation is not a quadratic equation.

Solution 1(v)
7x3 – 2x2 + 10 = (2x – 5)2
⇒ 7x3 – 2x2 + 10 = 4x2 – 20x + 25
⇒ 7x3 – 6x2 + 20x – 15 = 0; which is not of the form ax2 + bx + c = 0.
∴ Given equation is not a quadratic equation.

Solution 1(vi)
(x – 1)2 + (x + 2)2 + 3(x +1) = 0
⇒ x2 – 2x + 1 + x2 + 4x + 4 + 3x + 3 = 0
⇒ 2x2 + 5x + 8 = 0; which is of the form ax2 + bx + c = 0.
∴ Given equation is a quadratic equation.

Question 2(i)
Is x = 5 a solution of the quadratic equation x2 – 2x – 15 = 0?
Solution:
x2 – 2x – 15 = 0
For x = 5 to be solution of the given quadratic equation it should satisfy the equation.
So, substituting x = 5 in the given equation, we get
L.H.S = (5)2 – 2(5) – 15
= 25 – 10 – 15
= 0
= R.H.S
Hence, x = 5 is a solution of the quadratic equation x2 – 2x – 15 = 0.

Question 2(ii).
Is x = -3 a solution of the quadratic equation 2x2 – 7x + 9 = 0?
Solution:
2x2 – 7x + 9 = 0
For x = -3 to be solution of the given quadratic equation it should satisfy the equation
So, substituting x = 5 in the given equation, we get
L.H.S =2(-3)2 – 7(-3) + 9
= 18 + 21 + 9
= 48
≠ R.H.S
Hence, x = -3 is not a solution of the quadratic equation 2x2 – 7x + 9 = 0.

Question 3.
If $$\sqrt{\frac{2}{3}}$$ is a solution of equation 3x2 + mx + 2 = 0, find the value of m.
Solution:
For x = $$\sqrt{\frac{2}{3}}$$ to be solution of the given quadratic equation it should satisfy the equation
So, substituting x = $$\sqrt{\frac{2}{3}}$$ in the given equation, we get

Question 4.
$$\frac{2}{3}$$ and 1 are the solutions of equation mx2 + nx + 6 = 0. Find the values of m and n.
Solution:
For x =  $$\frac{2}{3}$$ and x = 1 to be solutions of the given quadratic equation it should satisfy the equation
So, substituting x =  $$\frac{2}{3}$$ and x = 1 in the given equation, we get

Solving equations (1) and (2) simultaneously,
4m  + 6n + 54 = 0 …..(1)
m + n  + 6 = 0 ….(2)
(1) – (2) × 6
⇒ -2m + 18 = 0
⇒ m = 9
Substitute in (2)
⇒ n = -15

Question 5.
If 3 and -3 are the solutions of equation ax2 + bx – 9 = 0. Find the values of a and b.
Solution:
For x = 3 and x = -3 to be solutions of the given quadratic equation it should satisfy the equation
So, substituting x = 3 and x = -3 in the given equation, we get

Solving equations (1) and (2) simultaneously,
9a + 3b – 9 = 0 …(1)
9a – 3b – 9 = 0 …(2)
(1) + (2)
⇒ 18a – 18 = 0
⇒ a = 1
Substitute in (2)
⇒ b = 0

### Quadratic Equations Exercise 5B – Selina Concise Mathematics Class 10 ICSE Solutions

Question 1.
Without solving, comment upon the nature of roots of each of the following equations :
(i) 7x2 – 9x +2 =0
(ii) 6x2 – 13x +4 =0
(iii) 25x2 – 10x +1=0
(iv) x2 + 2√3x – 9=0
(v) x2 – ax – b2 =0
(vi) 2x2 +8x +9=0
Solution:

Question 2.
Find the value of p, if the following quadratic equation has equal roots : 4x2 – (p – 2)x + 1 = 0
Solution:

Question 3.
Find the value of ‘p’, if the following quadratic equations have equal roots : x2 + (p – 3)x + p = 0
Solution:
x2 + (p – 3)x + p = 0
Here, a = 1, b = (p – 3), c = p
Since, the roots are equal,
⇒ b2– 4ac = 0
⇒ (p – 3)2– 4(1)(p) = 0
⇒p2 + 9 – 6p – 4p = 0
⇒ p2– 10p + 9 = 0
⇒p2-9p – p + 9 = 0
⇒p(p – 9) – 1(p – 9) = 0
⇒ (p -9)(p – 1) = 0
⇒ p – 9 = 0 or p – 1 = 0
⇒ p = 9 or p = 1

Question 4.
The equation 3x2 – 12x + (n – 5)=0 has equal roots. Find the value of n.
Solution:

Question 5.
Find the value of m, if the following equation has equal roots : (m – 2)x2 – (5+m)x +16 =0
Solution:

Question 6.
Find the value of p for which the equation 3x2– 6x + k = 0 has distinct and real roots.
Solution:

### Quadratic Equations Exercise 5C – Selina Concise Mathematics Class 10 ICSE Solutions

Question 1.
Solve : x² – 10x – 24 = 0
Solution:

Question 2.
Solve : x² – 16 = 0
Solution:

Question 3.

Solution:

Question 4.
Solve : x(x – 5) = 24
Solution:

Question 5.

Solution:

Question 6.

Solution:

Question 7.

Solution:

Question 8.

Solution:

Question 9.
Solve : (2x – 3)² = 49
Solution:

Question 10.
Solve : 2(x² – 6) = 3(x – 4)
Solution:

Question 11.
Solve : (x + 1)(2x + 8) = (x + 7)(x + 3)
Solution:

Question 12.
Solve : x² – (a + b)x + ab = 0
Solution:

Question 13.
(x + 3)² – 4(x + 3) – 5 = 0
Solution:

Question 14.
4(2x – 3)² – (2x – 3) – 14 = 0
Solution:

Question 15.

Solution:

Question 16.
2x2 – 9x + 10 = 0, When
(i) x∈ N
(ii) x∈ Q
Solution:

Question 17.

Solution:

Question 18.

Solution:

Question 19.

Solution:

Question 20.

Solution:

Question 21.
Find the quadratic equation, whose solution set is :
(i) {3, 5} (ii) {-2, 3}
Solution:

Question 22.

Solution:

Question 23.

Solution:

Question 24.
Find the value of x, if a + 1=0 and x2 + ax – 6 =0.
Solution:

Question 25.
Find the value of x, if a + 7=0; b + 10=0 and 12x2 = ax – b.
Solution:
If a + 7 =0, then a = -7
and b + 10 =0, then b = – 10
Put these values of a and b in the given equation

Question 26.
Use the substitution y= 2x +3 to solve for x, if 4(2x+3)2 – (2x+3) – 14 =0.
Solution:

Question 27.
Without solving the quadratic equation 6x2 – x – 2=0, find whether x = 2/3 is a solution of this equation or not.
Solution:

Question 28.
Determine whether x = -1 is a root of the equation x2 – 3x +2=0 or not.
Solution:
x2 – 3x +2=0
Put x = -1 in L.H.S.
L.H.S. = (-1)– 3(-1) +2
= 1 +3 +2=6 ≠ R.H.S
Then x = -1 is not the solution of the given equation.

Question 29.
If x = 2/3 is a solution of the quadratic equation 7x2+mx – 3=0; Find the value of m.
Solution:

Question 30.
If x = -3 and x = 2/3 are solutions of quadratic equation mx+ 7x + n = 0, find the values of m and n.
Solution:

Question 31.
If quadratic equation x2 – (m + 1) x + 6=0 has one root as x =3; find the value of m and the root of the equation.
Solution:

Question 32.
Given that 2 is a root of the equation 3x² – p(x + 1) = 0 and that the equation px² – qx + 9 = 0 has equal roots, find the values of p and q.
Solution:

Question 33.

Solution:

Question 34.

Solution:

Question 35.
If -1 and 3 are the roots of x2 + px + q = 0, find the values of p and q.
Solution:

### Quadratic Equations Exercise 5D – Selina Concise Mathematics Class 10 ICSE Solutions

Question 1.

Solution:

Question 2.
Solve each of the following equations for x and give, in each case, your answer correct to one decimal place :
(i) x2 – 8x+5=0
(ii) 5x2 +10x – 3 =0
Solution:

Question 3(i).
Solve each of the following equations for x and give, in each case, your answer correct to two decimal places :
(i) 2x2 – 10x +5=0
Solution:

Question 3(ii).
Solve each of the following equations for x and give, in each case, your answer correct to two decimal places :
4x + 6/x + 13 = 0
Solution:

Question 3(iii).
Solve each of the following equations for x and give, in each case, your answer correct to two decimal places :
x2 – 3x – 9 =0
Solution:

Question 3(iv).
Solve each of the following equations for x and give, in each case, your answer correct to two decimal places :
x2 – 5x – 10 = 0
Solution:

Question 4.
Solve each of the following equations for x and give, in each case, your answer correct to 3 decimal places :
(i) 3x2 – 12x – 1 =0
(ii) x2 – 16 x +6= 0
(iii) 2x2 + 11x + 4= 0
Solution:

Question 5.
Solve:
(i) x4 – 2x2 – 3 =0
(ii) x4 – 10x2 +9 =0
Solution:

Question 6.
Solve :
(i) (x2 – x)2 + 5(x2 – x)+ 4=0
(ii) (x2 – 3x)2 – 16(x2 – 3x) – 36 =0
Solution:

Question 7.

Solution:

Question 8.

Solution:

Question 9.
Solve the following equation and give your answer correct to 3 significant figures:
5x² – 3x – 4 = 0
Solution:

Question 10.
(x – 1)2 – 3x + 4 = 0
Solution:

Question 11.
Solve the quadratic equation x² – 3 (x+3) = 0; Give your answer correct to two significant figures.
Solution:

### Quadratic Equations Exercise 5E – Selina Concise Mathematics Class 10 ICSE Solutions

Question 1.

Solution:

Question 2.
Solve: (2x+3)2=81
Solution:

Question 3.
Solve: a²x² – b² = 0
Solution:

Question 4.

Solution:

Question 5.

Solution:

Question 6.
Solve: 2x4 – 5x² + 3 = 0
Solution:

Question 7.
Solve: x4 – 2x² – 3 = 0.
Solution:

Question 8.

Solution:

Question 9.

Solution:

Question 10.

Solution:

Question 11.
Solve : (x² + 5x + 4)(x² + 5x + 6) = 120
Solution:

Question 12.
Solve each of the following equations, giving answer upto two decimal places.
(i) x2 – 5x -10=0 (ii) 3x2 – x – 7 =0
Solution:

Question 13.

Solution:

Question 14.
Solve :
(i) x2 – 11x – 12 =0; when x ∈ N
(ii) x2 – 4x – 12 =0; when x ∈ I
(iii) 2x2 – 9x + 10 =0; when x ∈ Q
Solution:

Question 15.
Solve : (a + b)²x² – (a + b)x – 6 = 0; a + b ≠ 0
Solution:

Question 16.

Solution:

Question 17.

Solution:

Question 18.

Solution:

Question 19.

Solution:

Question 20.
Without solving the following quadratic equation, find the value of ‘m’ for which the given equation has real and equal roots.
x² + 2(m – 1)x + (m + 5) = 0
Solution:

### Quadratic Equations Exercise 5F – Selina Concise Mathematics Class 10 ICSE Solutions

Solution 1(i)
Given: (x + 5)(x – 5)=24
⇒ x2 – 52 = 24   …. since (a – b)(a + b) = a2 – b2
⇒ x2 – 25 = 24
⇒ x2 = 49
⇒ x = ± 7

Solution 1(ii)
Given: 3x2 – 2$$\sqrt{6}$$x + 2 = 0

Solution 1(iii)
Given: 3$$\sqrt{2}$$x2 – 5x – $$\sqrt{26}$$ = 0

Question 2.
One root of the quadratic equation 8x2 + mx + 15 is 3/4. Find the value of m. Also, find the other root of the equation.

Solution:
Given quadratic equation is  8x2 + mx + 15 = 0   …. (i)
One of the roots of (i) is $$\frac{3}{4}$$, so it satisfies (i)

So, the equation (i) becomes 8x2 – 26x + 15 = 0
⇒ 8x2 – 20x – 6x + 15 = 0
⇒ 4x(2x – 5) -3(2x – 5) = 0
⇒ (4x – 3)(2x – 5) = 0
⇒ x = $$\frac{3}{4}$$ or x = $$\frac{5}{2}$$
⇒ x = $$\frac{3}{4}, \frac{5}{2}$$
Hence, the other root is $$\frac{5}{2}$$

Question 3.
One root of the quadratic equation x2 – 3x – 2ax – 6a = 0 is -3, find its other root.

Solution:
Given quadratic equation is …. (i)
One of the roots of (i) is -3, so it satisfies (i)
⇒ x2 – 3x – 2ax – 6a = 0
⇒ x(x + 3) – 2a(x + 3) = 0
⇒ (x – 2a)(x + 3) = 0
⇒ x = -3, 2a
Hence, the other root is 2a.

Question 4.
If p – 15 = 0 and 2x2 + 15x + 15 = 0;find the values of x.

Solution:
Given i.e p – 15 = 0 i.e. p = 15
So, the given quadratic equation becomes
2x2 + 15x + 15 = 0
⇒ 2x + 10x + 5x + 15 = 0
⇒ 2x(x + 5) + 5(x + 5)
⇒ (2x + 5)(x + 5) = 0
⇒ x = -5, $$-\frac{5}{2}$$
Hence, the values of x are -5 and $$-\frac{5}{2}$$

Question 5.
Find the solution of the equation 2x2 -mx – 25n = 0; if m + 5 = 0 and n – 1 = 0.

Solution:
Given quadratic equation is 2x2 -mx – 25n = 0 ….. (i)
Also, given and m + 5 = 0 and n – 1 = 0
⇒ m = -5 and n = 1
So, the equation (i) becomes
2x2 + 5x + 25 = 0
⇒ 2x + 10x – 5x – 25 = 0
⇒ 2x(x + 5) -5(x + 5) = 0
⇒ (x + 5)(2x – 5) = 0
⇒ x = -5, $$\frac{5}{2}$$
Hence, the solution of given quadratic equation are x and $$\frac{5}{2}$$

Question 6.
If m and n are roots of the equation $$\frac{1}{x}-\frac{1}{x-2}=3$$ where x ≠ 0 and x ≠ 2; find m × n.

Solution:
Given quadratic equation is $$\frac{1}{x}-\frac{1}{x-2}=3$$

Since, m and n are roots of the equation, we have

Question 7.
Solve, using formula :
x2 + x – (a + 2)(a + 1) = 0
Solution:
Given quadratic equation is x2 + x – (a + 2)(a + 1) = 0

Question 8.
Solve the quadratic equation 8x2 – 14x + 3 = 0
(i) When x ∈ I (integers)
(ii) When x ∈ Q (rational numbers)
Solution:
Given quadratic equation is 8x2 – 14x + 3 = 0
⇒ 8x2 – 12x – 2x + 3 = 0
⇒ 4x(2x – 3) – (2x – 3) = 0
⇒ (4x – 1)(2x – 3) = 0
⇒ x = $$\frac{3}{2}$$ or x = $$\frac{1}{4}$$
(i) When x ϵ I, the equation 8x2 – 14x + 3 = 0 has no roots
(ii) When x ϵ Q the roots of 8x2 – 14x + 3 = 0 are
x = $$\frac{3}{2}$$ x = $$\frac{1}{4}$$

Question 9.
Find the value of m for which the equation (m + 4 )2 + (m + 1)x + 1 = 0 has real and equal roots.
Solution:
Given quadratic equation is (m + 4 )2 + (m + 1)x + 1 = 0
The quadratic equation has real and equal roots if its discriminant is zero.
⇒ D = b2 – 4ac = 0
⇒ (m + 1)2 -4(m + 4)(1) = 0
⇒ m2 + 2m + 1 – 4m – 16 = 0
⇒ m2 – 2m – 15 = 0
⇒ m2 – 5m + 3m – 15 = 0
⇒ m(m – 5) +3(m =5) = 0
⇒ (m – 5)(m + 3) = 0
⇒ m = 5 or m = -3

Question 10.
Find the values of m for which equation 3x2 + mx + 2 = 0 has equal roots. Also, find the roots of the given equation.
Solution:
Given quadratic equation is 3x2 + mx + 2 = 0 …. (i)
The quadratic equation has equal roots if its discriminant is zero
⇒ D = b2 – 4ac = 0
⇒ m2 – 4(2)(3) = 0
⇒ m2 = 24
⇒ m = $$\pm 2 \sqrt{6}$$
When m = $$2 \sqrt{6}$$, equation (i) becomes

When m = $$-2 \sqrt{6}$$, equation (i) becomes

∴ x= $$-\frac{\sqrt{6}}{3}, \frac{\sqrt{6}}{3}$$

Question 11.
Find the value of k for which equation 4x2 + 8x – k = 0 has real roots.

Solution:
Given quadratic equation is 4x2 + 8x – k = 0 …. (i)
The quadratic equation has real roots if its discriminant is greater than or equal to zero
⇒ D = b2 – 4ac ≥ 0
⇒ 82 – 4(4)(-k) ≥ 0
⇒ 64 + 16k ≥ 0
⇒ 16k ≥ -64
⇒ k ≥ -4
Hence, the given quadratic equation has real roots for k ≥ -4

Question 12.
Find, using quadratic formula, the roots of the following quadratic equations, if they exist
(i) 3x2 – 5x + 2 = 0
(ii) x2 + 4x + 5 = 0
Solution:
(i) Given quadratic equation is 3x2 – 5x + 2 = 0
D = b2 – 4ac = (-5)2 – 4(3)(2) = 25 – 24 = 1
Since D > 0, the roots of the given quadratic equation are real and distinct.

⇒ x = 1 or x = $$\frac{2}{3}$$

(ii) Given quadratic equation is x2 + 4x + 5 = 0
D = b2 – 4ac = (4)2 – 4(1)(5) = 16 – 20 = – 4
Since D < 0, the roots of the given quadratic equation does not exist.

Solution 13:
(i) Given quadratic equation is $$\frac{1}{18-x}-\frac{1}{18+x}=\frac{1}{24}$$

⇒ 48x = 324 – x2
⇒ x2 + 48x – 324 = 0
⇒ x2 + 54x – 6x – 324 = 0
⇒ x(x + 54) -6(x + 54) = 0
⇒ (x + 54)(x – 6) = 0
⇒ x = -54 or x = 6
But as x > 0, so x can’t be negative.
Hence, x = 6.
(ii) Given quadratic equation is $$(x-10)\left(\frac{1200}{x}+2\right)=1260$$
⇒ (x – 10)$$\left(\frac{1200+2 x}{x}\right)$$ = 1260
⇒ (x – 10)(1200 + 2x) = 1260x
⇒ 1200x + 2x2 – 12000 – 20x = 1260x
⇒ 2x2 – 12000 – 80x = 0
⇒ x2 – 40x – 6000 = 0
⇒ x2 – 100x + 60x – 6000 = 0
⇒ (x – 100)(x – 60) = 0
⇒ x = 100 or x = -60
But as x < 0, so x can’t be positive.
Hence, x = -60.

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## ML Aggarwal ICSE Solutions for Class 6 to 10

The ML Aggarwal Solutions for ICSE Maths has been written as per the latest guidelines and in conformance to the syllabus issued by the Council for ICSE examinations. The new syllabus will be able to best meet the expectations and learning objectives of the students.

ML Aggarwal ICSE Solutions

The subject matter contained in this Understanding ICSE Mathematics ML Aggarwal Solved Solutions has been explained in a simple language and includes many examples from real life situations. Emphasis has been laid on basic facts, concepts, terms, principles and on their applications. Carefully selected examples consist of detailed step-by-step solutions so that the students get prepared to tackle all the problems given in exercises.

Salient features of the ML Aggarwal Solutions:

• Keeping in mind the age group of the students, the matter has been divided into sections and sub-sections so that the students can learn at their own pace.
• All new concepts have been developed by class-activity method. The practical hand-on experience of these activities will enable the students to visualise and develop a deeper understanding of the concepts.
• Results, wherever possible, have been verified by lab activity method.
• Questions in the form of Fill in the Blanks, True/False statements and Multiple Choice Questions, given under the heading ‘Mental Maths’, have been added for the objective assessment of the concepts.
• In addition to standard questions, some Higher Order Thinking Skills (HOTS) questions have been included to enhance the analytical thinking of the students.
• Each chapter is followed by a Summary which recapitulates the new terms, concepts and results.
• The last section ‘Check Your Progress’, acts as a Unit Test.
• Model Question Papers, given at various places, will serve as means for revision and preparation for the exams.

### FAQs on ML Aggarwal Solutions

You can download them from our page through the quick links available or even find them online.

2. Where will I find ML Aggarwal Classwise Solutions?

Candidates are advised to ML Aggarwal Questions on their own. If you are stuck at some point you can find them on our website and clarify your doubts.

3. Is ML Aggarwal the right book for ICSE?

The most fundamental book when it comes to preparing for ICSE is NCERT Textbooks. Once, you are done with the preparation you can refer to the ML Aggarwal Books, and Practicing the questions in them is essential for an ICSE Student.

4. Does solving ML Aggarwal Solutions benefit you during your exam preparation?

Yes, it can be of huge benefit as you will have in-depth knowledge about the related topic. ML Aggarwal ICSE Solutions designed for ICSE Students will enhance your problem solving skills.

5. Is solving examples from ML Aggarwal enough for the ISC?

Solving the examples in ML Aggarwal will give you a clear understanding of Fundamentals and you will know how to approach to a question.

It has been sincere endeavour to present the concepts, examples and questions in a coherent and interesting manner so that the students develop an interest in ‘learning’ and ‘enjoying’ mathematics. We thank publishers M/s Arya Publications (APC Maths Solutions ICSE) and Laser Tech Prints for their friendly cooperation and untiring efforts in bringing out this ML Aggarwal Maths for ICSE Solutions in an excellent form. We highly appreciate if you suggest any improvement you would like to see in the ML Aggarwal ICSE Solutions in its next edition.

## ICSE Class 10 Physics Previous Years Question Papers Solved Last 10 Years

APlusTopper.com provides ICSE Class 10 Physics Previous Year Board Question Papers Solved Pdf Free Download with Solutions, Answers and Marking Scheme. Here we have given ICSE Class 10 Physics Solved Question Papers Last Ten Years. Students can view or download the ICSE Board 10th Physics Previous Year Question Papers with Solutions for their upcoming examination.

These ICSE Class 10 Physics Previous 10 Years Board Question Papers with Answers are useful to understand the pattern of questions asked in the board exam. Know about the important concepts to be prepared for ICSE Class 10 Board Exam and Score More marks.

Board – Indian Certificate of Secondary Education (ICSE), www.cisce.org
Class – Class 10
Subject – Physics
Year of Examination – 2020, 2019, 2018, 2017.

## ICSE Class 10 Physics Solved Question Papers Last Ten Years

ICSE Physics Class 10 Previous Years Question Papers Are Prepared By Our Experts In Accordance With The Guidelines Given By ICSE Board. ICSE Physics Class 10 Solved Question Papers Will Help, Students Gain Confidence And Make Them Ready To Face Their ICSE Board Exams. ICSE Physics Class 10 Question Papers Cover Important Concepts From An Examination Perspective. ICSE Class 10 Physics Model Solutions Are Also Provided To Help Self-Evaluation.

We hope the ICSE Class 10 Physics Previous Years Question Papers Solved Last 10 Years Pdf Free Download with Solutions will help you. If you have any query regarding ICSE Class 10 Physics Solved Question Papers Last Ten Years with Answers, drop a comment below and we will get back to you at the earliest.

## ICSE Class 10 History and Civics Previous Years Question Papers Solved Last 10 Years

APlusTopper.com provides ICSE Class 10 History and Civics Previous Year Board Question Papers Solved Pdf Free Download with Solutions, Answers and Marking Scheme. Here we have given ICSE Class 10 History and Civics Solved Question Papers Last Ten Years. Students can view or download the ICSE Board 10th History and Civics Previous Year Question Papers with Solutions for their upcoming examination.

These ICSE Class 10 History and Civics Previous 10 Years Board Question Papers with Answers are useful to understand the pattern of questions asked in the board exam. Know about the important concepts to be prepared for ICSE Class 10 Board Exam and Score More marks.

Board – Indian Certificate of Secondary Education (ICSE), www.cisce.org
Class – Class 10
Subject – History and Civics
Year of Examination – 2020, 2019, 2018, 2017.

## ICSE Class 10 History and Civics Solved Question Papers Last Ten Years

We hope the ICSE Class 10 History and Civics Previous Years Question Papers Solved Last 10 Years Pdf Free Download with Solutions will help you. If you have any query regarding ICSE Class 10 History and Civics Solved Question Papers Last Ten Years with Answers, drop a comment below and we will get back to you at the earliest.

## ICSE Time Table for Class 9 (Released) 2020 | CISCE Class IX Annual Exam Dates Out @ cisce.org

ICSE Class 9 Time Table 2020: ICSE Class 9th Time Table 2019 November session released and at the same time for February 2020 session also released. CISCE had released ICSE Class 9th Board Time Table for both the sessions on its official website @ cisce.org. ICSE Class 9/IX Annual exams will be commenced from February 10, 2020, to February 26, 2020.

Students are allowed to download ICSE 9th Class Board Exam Time Table 2019 and ICSE 2020 Timetable class 9 in PDF. If you check the ICSE Class 9 Board Exam Time Table 2020 then you will know about exam dates. Class 11 and Class 12 will come under ICSE Board.

## ICSE Class 9 Board Exam Time Table 2020

CISCE is an exam conducting authority for the organization of the Indian Certificate of Secondary Education (ICSE) Class IX Central Board examination for the entire Indian country. Every year in November 2019 and February 2020, the official board will release the exam dates of the ICSE Class 9 Board Exam Schedule.

### ICSE Class 9th Date Sheet 2020 Overview

 Board Name Council for the Indian School Certificate Examinations (CISCE) Course Name ICSE (9th/IX) Name of Exam Annual Exams – November 2019 and February 2020 Session Exam Dates 4th to 20th November 2019 10th February to February 26th Time Table Status Available Now Mode of Time Table Online Official Site cisce.org

### ICSE Class 9 Date Sheet February 2020

Every Studnet can download ICSE Class 9 Time Table directly from this page. Follow the steps to download ICSE Class 9 Date Sheet which is explained clearly in the next section. The Class 9 time table has been officially released by the Indian School Certificate Examinations Council (CISCE) through its website – cisce.org. ICSE Class 9 Board Exam 2020 will starts from 10th February 2020.

### ICSE Class 9 Date Sheet 2020 February

ICSE Class 9 Board Exam 2020 will starts from 10th February 2020. ICSE 9th Board Exam 2020 Time Table is as follows:

 Date and Day of Examination Subject and Paper 10th February 2020, Monday Literature in English – English Paper 2 11th February 2020, Tuesday English Language – English Paper 1 12th February 2020, Wednesday History & Civics – H.C.G. Paper 1 13th February 2020, Thursday Economics (Group II Elective) 14th February 2020, Friday Geography – H.C.G. Paper 2 17th February 2020, Monday Mathematics 20th February 2020, Wednesday Physics – Science Paper 1 24th February 2020, Friday Chemistry – Science Paper 2 25th February 2020, Monday Commercial Studies (Group II Elective) 26th February 2020, Wednesday Biology – Science Paper 3

ICSE Class 9th Date Sheet 2020 – February

Exam Timings:

• 9:00 AM to 11:00 AM (2 Hours, For all subjects except Maths)
• 9:00 AM to 11:30 AM (2 1/2 Hours, For Maths)

Important Notes

• In addition to the time indicated on the Time Table for writing the Paper, 15 minutes’ time must be given to the candidates for reading the Question Paper.
• The Question Paper may be distributed to candidates at 8.45 AM to enable them to start writing at 9:00 AM.

• Step – 1: Visit the official website of CISCE @  cisce.org.
• Step – 2: On the home page check for Notice Board Section.
• Step – 3: Now Click on that and search for the link download the ICSE 9th Class Board Exam Time Table 2019 and ICSE 9th Class Board Exam Time Table 2020.
• Step – 4: Now click on “ICSE (Class IX) Annual Examination Timetable – November 2019” and “ICSE (Class IX) Annual Examination Timetable – February 2020.”
• Step – 5: Now you will be redirected to the new page which shows the ICSE Class 9 Annual Examination Date Sheet.
• Step – 6: Download the PDF and save it for future reference.

### Details Mentioned on the ICSE Class 9 Time Table 2020

There are some important details available on the ICSE 9th Board Exam Time Table 2020. Students can check these details from below:

1. Examination Name
2. Board Name
3. Respective Class
4. Date and Day of Examination
5. Examination Timing
6. Duration of Examination
7. Important Instruction+

#### Board Exam Time Table 2020

We hope we have provided all the necessary information about ICSE Class 9 Time Table 2020. If you have any doubts regarding this post or ICSE Class 9 Date Sheet 2020, please comment in the comment section we will get back to you at the earliest.

## ICSE Biology Previous year Question Paper 2019 Solved for Class 10

### ICSE 2019 Biology Board Question Paper Solved

General Instructions:

• Answers to this Paper must be written on the paper provided separately.
• You will not be allowed to write during the first 15 minutes.
• This time is to be spent in reading the Question Paper.
• The time given at the head of this paper is the time allowed for writing the answers.
• Attempt all questions from Section I and any four questions from Section II.
• The intended marks for questions or parts of questions are given in brackets [ ].

Section -1 (40 Marks)
(Attempt All questions from this section)

Question 1.
(a) Name the following : [5]
(i) The layer of the eyeball that provide nourishment to the eye.
(ii) One gaseous compound which depletes the ozone layer.
(iii) The structure which connects the placenta and the foetus.
(iv) A pair of corresponding chromosomes of the same shape and size and derived one from each parent.
(v) The compound formed when haemoglobin combines with carbon dioxide in blood.
(i) Choroid

(ii) Chlorofluorocarbon

(iii) Umbilical Cord

(iv) Homologous Chromosome

(v) Carbaminohaemoglobin

(b) Correct and rewrite the statement by changing the biological term that is underlined for each statement: [5]
(i) The theory of Inheritance of Acquired Characters was proposed by Watson and Crick.
(ii The protective sac which develops around the developing embryo is called the Pericardium.
(iii) Maintaining balance of the body and coordinating muscular activities is carried by the cerebrum.
(iv) The kidney is composed of number of neurons.
(v) The part of the eye which can be donated from a clinically dead person is the Retina.
(i) The theory of inheritance of Acquired Characters was proposed by Jean Baptiste de Lamark.

(ii) The protective sac which develops around the developing embryo is called amnion.

(iii) Maintaining balance of the body and coordinating muscular activities is carried out by the Cerebellum.

(iv) The kidney is composed of number of nephrons.

(v) The part of the eye which can be donated from a clinically dead person is cornea.

(c) Give suitable biological reasons for the following statements : [5]
(i) The birth rate in India is very high.
(ii) Carbon monoxide is dangerous when inhaled.
(in) Root hairs become flaccid and droop when excess fertilizers are added to the moist soil around them.
(iv) Acid rain is harmful to the environment.
(v) All life on Earth is supported by Photosynthesis.
(i) Due to better medical care there is a fall in death rate both for infants and the old. As long as birth rate exceeds death rate population grows rapidly.

(ii) Haemoglobin has very strong affinity for carbon monoxide, forming a stable compound carboxyhaemoglobin. This cuts down the capacity of blood for transporting oxygen, sometimes resulting in death.

(iii) Excessive fertilizers make the soil hypertonic as compared to root hair cells. Exosmosis takes place and root hair cells become flaccid due to which they droop.

(iv) Acid rain is dangerous for vegetation, decays building materials, paints and corrodes building and monuments and statues. It acidifies lakes and streams which affect aquatic life.

(v) Provides oxygen for respiration. Provides food and maintains food chain.

(d) Match the items given in Column A with the most appropriate ones in Column B and rewrite the correct matching pairs. [5]

(e) Choose the correct answer from the four options given below : [5]

(i) While recording the pulse rate, where exactly does a doctor press on our wrist?
A. Nerve
B. Vein
C. Artery
D. Capillary
C. Artery

(ii) In a human male, a sperm will contain :
A. Both X and Y chromosomes
B. Only Y Chromosomes
C. Only X chromosome
D. Either X or Y Chromosomes
A. Both X and Y chromosomes

(iii) A muscular wall is absent in :
A. Capillary
B. Venule
C. Arteriole
D. Vein
A. Capillary

(iv) On which day of the menstrual cycle does ovulation take place ?
A. 5th day
B. 28th day
C. 14th day
D. 1st day
C. 14th day

(v) Which one of the following does not affect the rate of transpiration ?
A. Light
B. Humidity
C. Wind
D. Age of the plant
D. Age of the plant

(f) Identify the ODD term in each set and name the CATEGORY to which the remaining three belong : [5]
Example: glucose, starch, cellulose, calcium, Odd term: calcium.
(i) Addison’s disease, Cushing’s Syndrome, Acromegaly, Leukemia.
(iii) Axon, Dendron, Photon, Cyton.
(iv) Chicken pox, Colour blindness, Haemophilia, Albinism.
(v) Polythene bag, Crop residue, Animal waste, Decaying vegetable.

(g) Expand the following biological abbreviations : [5]
(i) ABA
(ii) IAA
(iii) ATP
(iv) DNA
(v) TSH
(i) Abscisic acid

(ii) Indole acetic acid

(iv) Deoxyribonucleic acid

(v) Thyroid stimulating hormone

(h) Study the picture given below and answer the following questions: [5]

(i) Identify the type of pollution.
(ii) Name one pollutant that causes the above pollution.
(iii) Mention the impact of this pollution on human health.
(iv) State one measure to control this pollution.
(v) What is a ‘Pollutant’? Explain the term.
(i) Water pollution

(ii) Detergents, Chemicals

(iii) Cholera, Jaundice, Typhoid, Dysentery, Diarrhoea

(iv) We should treat the poisonous substances and discharge materials and toxic substances coming out of the homes and factories before discharging them into the rivers and ponds. We should not mix petroleum substances in the water. Dead bodies should not be thrown in the river. We should set more and more sewage treatment plants that play a crucial role in the reclaimed polluted water. Effective steps should be taken to outlaw dumping of wastes into a river or other water sources.

(v) Agents causing pollution are called pollutants.
Example, Gaseous pollutants are so, co2 and co.
Chemical pollutants like fertilizers, pesticide and insecticide.

Section – II (40 Marks)
Attempt any four questions from this Section.

Question 2.
Given below is an experimental setup to demonstrate a particular tropic movement in germinating seeds. Study the diagram and answer the questions that follow : [5]

(i) Label the parts 1 and 2.
(ii) Name the tropic movement shown by part 1.
(iii) Part 1 is affected by two stimuli. Name them. Which one of the two is stronger?
(iv) What is Thigmotropism ? Give one example.
(v) What is meant by ‘Positive’ and ‘Negative’ tropic movements in plants?
(i) 1 – Radicle 2 – Plumule

(ii) Hydrotropism

(iii) Gravity and Water – Water is stronger.

(iv) Growth movement of plants in response to touch stimulus, e.g., Sweet Pea

(v) Movement of parts of plant towards source of stimulus is positive and away from source of stimulus is negative.

(b) Mention the exact location of the following : [5]
(i) Testis
(ii) Incus
(iii) Thylakoids
(iv) Amniotic fluid
(v) Corpus callosum
(i) Inside Scrotum

(ii) Between malleus and stapes.

(iii) In the stroma (matrix) of chloroplast

(iv) Cavity between amnion and embryo

(v) Between two cerebral hemispheres.

Question 3.
(a) The diagram given below represents an experiment to prove the importance of a factor in photosynthesis. Answer the questions that follow : [5]

(i) Name the factor studied in this experiment.
(ii) What will you observe in the experimental leaf after the starch test?
(iii) Explain the process of Photosynthesis.
(iv) Give a balanced chemical equation to represent the process of photosynthesis.
(v) Draw a neat, labelled diagram of an experimental setup to show that oxygen is released during photosynthesis.
(i) Sunlight

(ii) The exposed parts will turn blue-black with iodine solution while the part covered with black paper strip turns brown.

(iii) The process by which green plants containing chlorophyll produce food (glucose) from carbon dioxide and water by using light energy.

(iv)

(v)

(b) State the main functions of the following : [5]
(i) Medulla Oblongata
(ii) Cytokinins
(iii) Tears
(iv) Coronary Artery
(v) Seminal Vesicles
(i) Controls involuntary activities

(ii) Expansion of cotyledons, inhibits apical dominance, cell elongation.

(iii) Helps in killing germs, lubricates surface of eye.

(iv) Supply blood to heart muscles.

(v) Produces secretion which serves as a mediums for transportation of sperms which forms semen.

Question 4.
(a) The diagram given below represents an organ system in the human body. Study the same and answer the questions that follow : [5]

(i) Identify the system.
(ii) Label the parts marked 2 and 4. Mention the function of part 5.
(iii) Name the structural and functional units of the part marked 1.
(iv) What is the fluid that accumulates in part 3? Which is the main nitrogenous waste present in it?
(v) Draw a neat, labelled diagram showing the longitudinal section of part 1.
(i) Urinary / Excretory system

(ii) 2 – Left Ureters
4 – Sphincter muscle
5 – Urine is expelled from urinary bladder through urethra.

(iii) Nephron

(iv) Urine; main nitrogenous water present in it is urea.

(v)

(b) The diagram given below represents an endocrine gland in the human body. Study the diagram and answer the following questions : [5]

(i) Identify the endocrine gland. Where is it located?
(ii) Why is the above gland referred to as the ‘Master gland’?
(iii) Name the hormone which in deficiency causes Diabetes Insipidus. How does this disorder differ from Diabetes Mellitus ?
(iv) Explain the term ‘Hormone’.
What is the role of Tropic hormones in the human body?
(v) Which lobe of the above gland secretes :

1. Oxytocin
2. ACTH
3. Growth hormone

(i) Pituitary gland.
Location – Hangs from the base of midbrain below hypothalamus of brain.

(ii) Because it controls practically all other endocrine gland.

(iii) Antidiuretic hormone ; Its deficiency causes diabetes insipidus (hypoglycemia). Insufficient secretion of insulin causes diabetes mellitus (hyperglycemia). It passes sugar in urine.

(iv) Hormone is the secretion from some glandular part of the body which is poured directly into blood and which acts on target organs or cells of same individual, bringing about coordination between distant parts of the body.
Tropic hormones stimulate other endocrine gland to produce their specific hormone.

(v)

1. Posterior lobe
2. Anterior lobe
3. Anterior lobe

Question 5.
(a) Given below is an apparatus which was set up to investigate a physiological process in plants. The setup was placed in bright sunlight. Answer the questions that follow : [5]
(i) Identify Australopithecus and Neanderthal man from the above pictures.
(ii) Mention two characteristic features each for the two stages.
(iii) Who proposed the theory of ‘Natural Selection’ ?
(iv) Name the organism used as an example to explain ‘Industrial Melanisum’.
(v) Give two examples of Vestigial organs in humans.
(i) Transpiration, It is the loss of water in the form of water vapour from aerial exposed parts of plants.

(ii) To prevent escape of water vapour from the pot.

(iii)

• Intensity of sunlight
• Increase in temperature

(iv)

• Sunken stomata
• Thick cuticle

(v)

(b) Given below are two stages in the evolution of man. study them and answer the questions that follow: [5]

(i) Identify Australopithecus and Neanderthal man from the above pictures.
(ii) Mention two charcterstic feature each for the two stages.
(iii) Who proposed the theory of ‘Natural Selection’?
(iv) Name the organism used as an example to ‘Industrial Melanisum’.
(v) Give two examples of vestigial organs in humans.
(i) A – Neanderthal
B – Australopithecus

(ii) A – Height 600 cm, cranial capacity 1450 cm3
B – Height 120 cm, cranial capacity 450 – 600 cm3

(iii) Charles Darwin

(iv) peppered moth (Biston bitularia)

(v) Vermiform Appendix ; Wisdom tooth

Question 6.
(a) In Mendel’s experiments, tall pea plants (T) are dominant over dwarf pea plants (t). [5]
(i) What is the phenotype and genotype of the Fgeneration if a homozygus tall plant is crossed with a homozygus dwarf plant?
(ii) Draw a Punnett square board to show the gametes and offspring when both the parents the heterozygus for tallness.
(iii) What is the Phenotypic ratio and genotypic ratio of the above cross in (ii)?
(iv) State Mendel’s Law of Dominance.
(v) What is a Dihybrid Cross?
(i) Phenotype of Fgeneration is all are tall plants.
Genotype of Fgeneration is all plants are Tf.

(ii) Punett square is as follows :

(iii) Phenotypic ratio = 3:1
Genotypic ratio = 1:2:1

(iv) In a heterozygous condition, out of the two contrasting alleles, one expresses itself morphologically and other remains unexpressed. The factor which expresses itself phenotypically is called dominant and the other which remains unexpressed is called recessive.

(v) A cross between two individuals having two pairs of contrasting traits producing a generation in which all individuals are heterozygous for both the characters.

(b) Given below is a diagram representing a stage during the mitotic cell division. Study the diagram and answer the following questions : [5]

(i) Identify the stage by giving a suitable reason.
(ii) Is it a plant or an animal cell ? Give a reason to support your answer.
(iii) Draw a neat, labelled diagram of the stage which follows the one shown in the diagram.
(iv) How many chromosomes will each daughter cell have after the completion of the above division ?
(v) Name the four nitrogenous bases.
(i) Anaphase: Two sister chromatids move towards opposite poles.

(ii) Animal cell: No cell wall; presence of centrioles at opposite poles.

(iii)

(iv) Four

Question 7.
(a) Answer the following questions briefly : [5]
(i) How are the cytons and axons placed in the brain and the spinal cord ?
(it) Which part of the human ear gives ‘Dynamic balance’ and ‘Static balance’ to the body ?
(in) Explain how the human eye adapts itself to bright light and dim light.
(iv) What is Parthenocarpy ? Give one example.
(v) Mention any two objectives of ‘Swachh Bharat Abhiyan’.
(i) In brain, outer portion contains cyton which gives a grayish colour hence called as gray matter, while axon is inside.
In spinal cord, cyton’is inside forming gray matter and axon is outside forming white matter.

(ii) Dynamic balance – semicircular canal
Static balance – utriculus and sacculus (vestibule)

(iii) When a person moves from dark lighted area to brightly lighted area, visual purple of rods is bleached reducing their sensitivity and pupil constricts to reduce the amount of light entering eyes. This is light adaptation.
When a person moves from brightly lighted area to dark area, visual purple of rods which were earlier broken due to bright light regenerates and pupil dilates to allow more light to enter. This is dark adaptation.

(iv) Development of fruit without fertilization, e.g., Apple, banana, tomato.

(v)

• Eliminate open defecation by constructing community toilets.
• Neat and Clean India

(b) The diagram given below represents a system in the human body. Study the diagram and answer the following questions :  [5]

(i) Identify the system.
(ii) Label the parts marked 5 and 6.
(iii) Name the two hormones secreted by 1.
(iv) Mention the number and the name of the part involved in fertilization and implantation from the above diagram.
(v) Mention the surgical methods of contraception in :

1. Human males.
2. Human females.

(i) Human reproductive system

(ii) 5 – Oviducal funnel
6 – Cervix

(iii) Oestrogen, Progesterone

(iv) 2 (Fallopian tube) for fertilization
3 (Uterus) for implantation

(v) 1 – Vasecomy (in males)
2 – Tubectomy (in females)

## ICSE Physics Previous Year Question Paper 2019 Solved for Class 10

ICSE Class 10 Physics Board Question Paper 2019 Solved Pdf

General Instructions :

• Answers to this Paper must he written on the paper provided separately.
• You will not be allowed to write during the first 15 minutes.
• This time is to he spent in reading the question paper.
• The time given at the head of this Paper is the time allowed for writing the answers.
• Section I is compulsory. Attempt any four questions from Section II.
• The intended marks for questions or parts of questions are given in brackets [ ].

Section – I[40 Marks]
(Attempt all questions from this Section)

Question 1.
(a) The diagram below shows a claw hammer used to remove a nail:

(i) To which class of lever does it belong ?
(ii) Give one more example of the same class of lever mentioned by you in (i) for which the mechanical advantage is greater than one.
(b) Two bodies A and B have masses in the ratio 5:1 and their kinetic energies are in the ratio 125:9. Find the ratio of their velocities. [2]
(c) (i) Name the physical quantity which is measured in calories
(ii) How is calorie related to the SI unit of that quantity? [2]
(d) (i) Define couple.
(ii) State the SI unit of moment of couple. [2]
(e) (i) Define critical angle.
(ii) State one important factor which affects the critical angle of a given medium. [2]
(a) (i) Class One.
(ii) Shears used for cutting the thin metal sheets.

(b) Given

Kinetic energy is given by K = $$\frac { 1 }{ 2 }$$ mv2
Therefore,

(c) (i) Heat energy.
(ii) 1 cal = 4.2 J.

(d) (i) It is defined as a set of two equal and opposite forces acting along different lines
of action.
(ii) SI unit is N m.

(e) (i) It is the angle of incidence in the denser medium for which angle of refraction in the rarer medium is 90°.
(ii) Nature of the two media in contact.

Question 2.
(a) An electromagnetic radiation is used for photography in fog.
(ii) Why is this radiation mentioned by you, ideal for this purpose? [2]
(b) (b) (i) What is the relation between the refractive index of water with respect to air (aμw) and the refractive index of air with respect to water (wμa)
(ii) If the refractive index of water ivith respect to air (aμw) is $$\frac { 5 }{ 3 }$$. Calculate the refractive index of air ivith respect to water (wμa) [2]
(c) The specific heat capacity of a substance A is 3,800 J kg-1K-1 and that of a substance B is 400 J Kg-1K-1. Which of the two substances is a good conductor of heat? Give a reason for your answer. [2]
(d) A man playing a flute is able to produce notes of different frequencies. If he closes the holes near his mouth, will the pitch of the note produced, increase or decrease? Give a reason. [2]
(e) The diagram below shows a light source P embedded in a rectangular glass block ABCD of
critical angle 42°. Complete the path of the ray PQ till it emerges out of the block. [Write necessary angles.] [2]

(ii) Because it can penetrate fog.

(b)
(ii) Given (aμw) = $$\frac { 5 }{ 3 }$$

Therefore, We have

(c) Substance B. Because it requires relatively Httle heat to raise its temperature.

(d) The pitch will decrease, as the pitch is inversely proportional to the length of the vibrating air column.

(e) The path of ray is as shown:

Question 3.
(a) (i) If the lens is placed in water instead of air, how does its focal length change?
(ii) Which lens, thick or thin has greater focal length? [2]
(b) Two waves of the same pitch have amplitudes in the ratio 1 : 3.
What will be the ratio of their:
(i) intensities and
(ii) frequencies? [2]
(c) How does an increase in the temperature affect the specific resistance of a :
(i) Metal and
(ii) Semiconductor? [2]
(d) (i) Define resonant vibrations.
(ii) Which characteristic of sound, makes it possible to recognize a person by his voice without seeing him ? [2]
(e) Is it possible for a hydrogen (11H) nucleus to emit an alpha particle? Give a reason for your
(a) (i) Its focal length increases.
(ii) Thin lens.

(b) (i) Ratio of intensities will be 1: 9.
(ii) Ratio of frequencies will be 1:1.

(c) (i) Increases.
(ii) Decreases.

(d) (i) If a body is made to vibrate with its fundamental frequency by an external source, then the vibrations are called resonant vibrations.
(ii) Quality.

(e) No, as it does not possess a helium nucleus.

Question 4.
(a) Calculate the effective resistance across AB :

(b) (i) State whether the specific heat capacity of a substance remains the same when its state changes from solid to liquid.
(c) A magnet kept at the centre of two coils A and B is moved to and fro as shouni in the diagram. The two galvanometers show deflection.

State with a reason whether :
x > y or x <y [x and y are magnitudes of deflection] [2]
(d) (i) Why is a nuclear fusion reaction called a thermo nuclear reaction?
(ii) Complete the reaction : [2]
3 He2 + 2H14He2 +…….+Energy
(e) State two ways to increase the speed of rotation of a DC motor. [2]
(a) Resistors of 5 Ω and 4 Ω are in series, therefore, their net resistance is Rs = 5 + 4 = 9 Ω.
Now, this 9 Cl and 3 Ω are in parallel, hence net resistance RP = $$\frac{9 \times 3}{9+3}$$ = $$\frac { 18 }{ 12 }$$ = 1.5 Ω.
Now, this is in series with the 8 Cl resistor, hence net resistance of the circuit is RT = 8 + 1.5 = 9. 5

(b) (i) No, specific heat capacity does not remain the same when it changes from solid to liquid.
(ii) Let us take the example of water.
Specific heat capacity of water = 4.2 J kg-1 K-1
and specific heat capacity of ice = 2.1 J kg-1K-1

(c) x < y. This is because coil B has more number of turns.

(d) (i) Because this occurs at a very high temperature.
(ii) 3He2 + 2H14He2 + 1H1 + Energy

(e) The two ways are

1. Strong magnet and
2. High current.

Section – II [40 Marks]
(Attempt any four questions from this Section)

Question 5.
(a) A body of mass 10 kg is kept at a height of 5 m. It is allowed to fall and reach the ground.
(i) What is the total mechanical energy possessed by the body at the height of 2 m assuming it is a frictionless medium?
(ii) What is the kinetic energy possessed by the body just before hitting the ground? Take
g= 10 m s-2. [3]
(b) A uniform metre scale is in equilibrium as shown in the diagram :

(i) Calculate the weight of the metre scale.
(ii) Which of the following options is correct to keep the ruler in equilibrium when 40 gf wt is shifted to 0 cm mark?
F is shifted towards 0 cm or
F is shifted towards 100 cm. [3]
(c) The diagram below shows a pulley arrangement :

(i) Copy the diagram and mark the direction of tension on each strand of the string.
(ii) What is the velocity ratio of the arrangement?
(iii) If the tension acting on the string is T, then what is the relationship between T and effort E?
(iv) If the free end of the string moves through a distance x, find the distance by which the
(a) (i) The total mechanical energy is the total potential energy it possesses before its fall.
E = mgh = 10 × 10 × 5 = 500 J
It is equal to the maximum potential energy E = mgh = 10 × 10 × 5 = 500 J.

(b) (i) The weight of the metre scale acts at its centre of gravity i.e., at 50 cm mark.
By the concept of moments, we have
40 × (30 – 5 ) = W × (50 – 30)
or W = (40 × 25)/ 20 = 50 gf
(ii) F is shifted towards 0 cm.

(c) (i) The direction of tension is as marked.

(ii) VR = Distance travelled by effort/Distance travelled by load =$$\frac { 2x }{ 2 }$$ = 2.
The distance travelled by load is half the distance moved by effort = $$\frac { x }{ 2 }$$
(iii) T = E.
(iv) The distance travelled by load is half the distance moved by effort = $$\frac { x }{ 2 }$$ .

Question 6.
(a) How does the angle of deviation formed by a prism change with the increase in the angle of
incidence? Draw a graph showing the variation in the angle of deviation with the angle of incidence at a prism surface. [3]
(b) A virtual, diminished image is formed when an object is placed between the optical centre and the principal focus of a lens.
(i) Name the type of lens which forms the above image.
(ii) Draw a ray diagram to show the formation of the image with the above stated characteristics. [3]
(c) An object is placed at a distance 24 cm in front of a convex lens of focal length 8 cm.
(i) What is the nature of the image so formed ?
(ii) Calculate the distance of the image from the lens.
(iii) Calculate the magnification of the image. [4]
(a) As the. angle of incidence increases the angle of deviation decreases becomes minimum and then increases.
The graph is as shown :

(b) (i) Concave lens.
(ii) The ray diagram is as shown :

(c) Given u = – 24 cm, f= + 8 cm, v = ?
(i) Real, inverted and diminished.
(ii) Using the lens formula

(iii) Using the expression m =$$\frac { v }{ u }$$ = $$\frac { 12 }{ -24 }$$ = $$\frac { 1 }{ 2 }$$ .

Question 7.
(a) It is observed that during march-past we hear a base drum distinctly from a distance compared to the side drums.
(i) Name the characteristic of sound associated with the above observation.
(ii) Give a reason for the above observation. [3]
(b) A pendulum has a frequency of 4 vibrations per second. An observer starts the pendulum and fires a gun simultaneously. He hears the echo from the cliff after 6 vibrations of the pendulum. If the velocity of sound in air is 340 m s1, find the distance between the cliff and the observer. [3]
(c) Two pendulums C and D are suspended from a wire as shown in the given figure. Pendulum C is made to oscillate by displacing it from its mean position. It is seen that D also starts oscillating.

(i) Name the type of oscillation, C will execute.
(ii) Name the type of oscillation, D will execute.
(iii) If the length of D is made equal to C, then what difference will you notice in the oscillations ofD?
(iv) WHat is the name of the phenomenon when the length of D is made equal to C? [4]
(a) (i) Intensity of sound.
(ii) This is because the amplitude of vibration of a base drum is far greater than the amplitude of vibration of the side drum.

(b) Given f= 4 vbs, T = $$\frac { 1 }{ f }$$ = $$\frac { 1 }{ 4 }$$ = 0.25 s, for a frequency of 6 vbs titme t= $$\frac { 0.25 }{ 4 }$$ x 6 = 0.375 s, ,V=340ms-1
Using S = $$\frac{\mathbf{V} \times t}{2}$$ = $$\frac{340 \times 0.375}{2}$$ = 63.75 m

(c) (i) Free or natural oscillation.
(ii) Forced oscillation.
(iii) The amplitude of the oscillation of D will be equal to the amplitude of the oscillation of C.
(iv) Resonance.

Question 8.
(a) (i) Write one advantage of connecting electrical appliances in parallel combination.
(ii) What characteristics should a fuse wire have?
(iii) Which wire in a power circuit is connected to the metallic body of the appliance? [3]
(b) The diagram below shows a dual control switch circuit connected to a bulb.

(i) Copy the diagram and complete it so that the bulb is switched ON.
(ii) Out of A & B which one is the live wire and which one is the neutral wire?
(c) The diagram shows a circuit with the key k open.

Calculate:
(i) the resistance of the circuit when the key k is crpen.
(ii) the current drawn from the cell when the key k is open,
(iii) the resistance of the circuit when the key k is closed.
(iv) the current drawn from thexell when the key k is closed.
(a) (i) All appliances will continue to work even if one of the appliance does not work.
(ii) High resistivity and low melting point.
(iii) The ground wire.

(b) (i) The diagram is as shown :

(ii) A is connected to the live wire and B to neutral wire.

(c) (i) RS = 5 + 0.5 = 5.5 Ω
(ii) I=$$\frac { V }{ R }$$=$$\frac { 3.3 }{ 5.5 }$$= 0.6A
5×5
(iii) RP = $$\frac{5 \times 5}{5+5}$$ == 2.5 Ω, thus total resistance is RT = 2.5 +0.5 = 3.0

I= $$\frac{\mathrm{V}}{\mathrm{R}_{\mathrm{T}}}$$ = $$\frac { 3.3 }{ 3.0 }$$
= 1.1 A

Question 9.
(a) (i) Define Calorimetry.
(ii) Name the material used for making a Calorimeter.
(iii) Why is a Calorimeter made-up of thin sheets of the above material answered in (ii) ? [3]
(b) The melting point of naphthalene is 80°C and the room temperature is 30°C. A sample of
liquid naphthalene at 100°C is cooled down to the room temperature. Draw a temperature¬time graph to represent this cooling. In the graph, mark the region which corresponds to the freezing process. [3]
(c) 104 g of water at 30°C is taken in a calorimeter made of copper of mass 42 g. When a certain mass of ice at 0°C is added to it, the final steady temperature of the mixture after the ice has melted, was found to be 10°C. Find the mass of ice added.
[Specific heat capacity of water = 4.2 J g-1 °C-1  : Specific latent heat of fusion of ice – 336 J g-1 ; Specific heat capacity of copper = 0.4 J g-1 °C-1 ] [4]
(a) (i) Calorimetry is the measurement of heat,
(ii) Copper.
(iii) Copper has small specific heat capacity. The thin sheets ensure that the box has small heat capacity.

(b) The graph is as shown :

(c) Mass of water m1 = 104 g
Temperature of water T1 = 30°C
Final temperature T2 = 10°C
Mass of calorimeter m2 = 42 g
Temperature of ice T3= 0°C
Let the mass of ice added be = x g
Total heat energy lost = (104 × 4.2 × 20)+(42 × 0.4 × 20) = 8736 + 336 = 9072 J
Total heat energy gained = (336 × x)+(x × 4.2 × 10) = 336x + 42x = 378x
By principle of calorimetry,
Heat lost = Heat gained
378x =9072
x = $$\frac { 9072 }{ 378 }$$ = 24g

Question 10.
(a) Draw a neat labelled diagram of an AC generator.
(b) (i) Define nuclear fission.
(ii) Rewrite and complete the following nuclear reaction by filling in the atomic number of Ba and mass number of Kr : [3]

(c) The diagram below shows a magnetic needle kept just below the conductor AB which is kept in North South direction.

(i) In which direction does the needle deflect when the key is closed ?
(ii) Why is the deflection produced?
(iii) What will he the change in the deflection if the magnetic needle is taken just above the conductor AB ?
(iv) Name one device which works on this principle. [4]
(a) The diagram is as shown:

(b) (i) It is the splitting of a heavy nudeus into two or more smaller nudei with the
release of tremendous energy.
(ii)

(c) (i) East.
(ii) A current carrying conductor produces a magnetic field around itself.
(iii) The direction of deflection will reverse. (Towards west)
(iv) An electromagnet.

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